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Re: evaluate the floor s to yield a number

  • To: mathgroup at smc.vnet.net
  • Subject: [mg109011] Re: evaluate the floor s to yield a number
  • From: Murray Eisenberg <murray at math.umass.edu>
  • Date: Sat, 10 Apr 2010 06:53:37 -0400 (EDT)

What symbolic system are your trying to use?  Built-in objects in 
Mathematica have names beginning with upper-case letters; function calls 
surround their arguments with square-brackets, not parentheses.

In any case, I don't see any "s" in the output.

The relevant Mathematica function is -- guess what! -- Floor to 
calculate the floor of something. Of course you cannot expect it to do 
an actual evaluation of the Floor of something unless all the variables 
inside the argument already have actual numeric values.

On 4/9/2010 3:34 AM, John Ertle Jr. wrote:
> In[82]:= J =
>   367*y + floor (7*(y + floor ((m + 9)/12))/4) + int (275*m/9) + da +
>    1721013.5
>
> Out[82]= 2.44254*10^6 + 7/4 floor (1966 + (17 floor)/12) + (2200 int)/
>   9
>
> How do you evaluate the floor s in the output in this example to yield a number for the Julian Date.
>

-- 
Murray Eisenberg                     murray at math.umass.edu
Mathematics & Statistics Dept.
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University of Massachusetts                413 545-2859 (W)
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