Re: How to evaluate the Laplacian of a function as a function?

*To*: mathgroup at smc.vnet.net*Subject*: [mg114372] Re: How to evaluate the Laplacian of a function as a function?*From*: Iliyan Georgiev <me at iliyan.com>*Date*: Thu, 2 Dec 2010 05:41:01 -0500 (EST)*References*: <id4sma$ci5$1@smc.vnet.net>

OK, I got it - I should have used the replace all operator: funcLapl[x_,y_] := Laplacian[func[Xx,Yy]] /. {Xx->x, Yy->y} Hope it'll be a useful tip for others. On Dec 1, 8:15 am, Iliyan Georgiev <m... at iliyan.com> wrote: > Hi, > > I have a stupid problem and cannot find a solution anywhere. I have > the function > > func[x_,y_] := 3/Pi*(1 - x^2 + y^2))^2 > > which I need the Laplacian of: > > funcLapl := Laplacian[func[Xx,Yy]] > > The Laplacian is computed correctly, but how can I treat the result as > a function? I want to be able to evaluate/plot the Laplacian. I tried > many things and I'm frustrated. My current solution is to manually > copy the derived Laplacian and create a function from that. It's > obviously not a good solution. > > Any suggestions?