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Re: How to evaluate the Laplacian of a function as a function?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg114372] Re: How to evaluate the Laplacian of a function as a function?
  • From: Iliyan Georgiev <me at iliyan.com>
  • Date: Thu, 2 Dec 2010 05:41:01 -0500 (EST)
  • References: <id4sma$ci5$1@smc.vnet.net>

OK, I got it - I should have used the replace all operator:

funcLapl[x_,y_] := Laplacian[func[Xx,Yy]] /. {Xx->x, Yy->y}

Hope it'll be a useful tip for others.

On Dec 1, 8:15 am, Iliyan Georgiev <m... at iliyan.com> wrote:
> Hi,
>
> I have a stupid problem and cannot find a solution anywhere. I have
> the function
>
> func[x_,y_] := 3/Pi*(1 - x^2 + y^2))^2
>
> which I need the Laplacian of:
>
> funcLapl := Laplacian[func[Xx,Yy]]
>
> The Laplacian is computed correctly, but how can I treat the result as
> a function? I want to be able to evaluate/plot the Laplacian. I tried
> many things and I'm frustrated. My current solution is to manually
> copy the derived Laplacian and create a function from that. It's
> obviously not a good solution.
>
> Any suggestions?



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