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Re: factoring


It fails because the variables x, y, and z do not appear in the original  
expression. (It involves only the three variables xy, xz, and yz.)

This works, however:

Factor[x y - x z + y^2 - y z]

(x + y) (y - z)

Bobby

On Thu, 30 Dec 2010 03:09:17 -0600, r_poetic <radford.schantz at mms.gov>  
wrote:

> Hello,
> an easy question:
>
> why does Factor[xy-xz+y^2-yz] fail to return (x+y)(y-z), and what
> command would do that?
>
> Thanks!
>
>


-- 
DrMajorBob at yahoo.com


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