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Re: Square root of a square

• To: mathgroup at smc.vnet.net
• Subject: [mg107829] Re: Square root of a square
• From: Leonid Shifrin <lshifr at gmail.com>
• Date: Sun, 28 Feb 2010 04:51:28 -0500 (EST)
• References: <201002270813.DAA11868@smc.vnet.net>

Hi Mariano,

The first result (that Sqrt[x^2] does not simplify further without
additional assumptions) was expected. However, the second result (that
Mathematica simplifies Sqrt[x^2] == x to True)  looks like a bug to me.

Regards,
Leonid


On Sat, Feb 27, 2010 at 11:13 AM, Mariano Su=E1rez-Alvarez <
mariano.suarezalvarez at gmail.com> wrote:

> Hi all,
>
> Mathematica evaluates FullSimplify[Sqrt[x^2]] to Sqrt[x^2], while it
> tells me that FullSimplify[Sqrt[x^2] == x] is True.
> Are these the expected answers?
>
> -- m
>
>

• References:
  • Square root of a square
    • From: Mariano Suárez-Alvarez <mariano.suarezalvarez@gmail.com>