Re: Square root of a square
- To: mathgroup at smc.vnet.net
- Subject: [mg107829] Re: Square root of a square
- From: Leonid Shifrin <lshifr at gmail.com>
- Date: Sun, 28 Feb 2010 04:51:28 -0500 (EST)
- References: <201002270813.DAA11868@smc.vnet.net>
Hi Mariano, The first result (that Sqrt[x^2] does not simplify further without additional assumptions) was expected. However, the second result (that Mathematica simplifies Sqrt[x^2] == x to True) looks like a bug to me. Regards, Leonid On Sat, Feb 27, 2010 at 11:13 AM, Mariano Su=E1rez-Alvarez < mariano.suarezalvarez at gmail.com> wrote: > Hi all, > > Mathematica evaluates FullSimplify[Sqrt[x^2]] to Sqrt[x^2], while it > tells me that FullSimplify[Sqrt[x^2] == x] is True. > Are these the expected answers? > > -- m > >
- References:
- Square root of a square
- From: Mariano Suárez-Alvarez <mariano.suarezalvarez@gmail.com>
- Square root of a square