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Re: Square root of a square

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  • Subject: [mg107841] Re: Square root of a square
  • From: Bob Hanlon <hanlonr at>
  • Date: Sun, 28 Feb 2010 04:53:44 -0500 (EST)
  • Reply-to: hanlonr at

FullSimplify[Sqrt[x^2] == x]


This is wrong since for real x, Sqrt is always non-negative and x could be =

x = -3;

Sqrt[x^2] == x


Bob Hanlon

---- "Mariano Su=C3=A1rez-Alvarez" <mariano.suarezalvarez at> wrote:=

Hi all,

Mathematica evaluates FullSimplify[Sqrt[x^2]] to Sqrt[x^2], while it
tells me that FullSimplify[Sqrt[x^2] == x] is True.
Are these the expected answers?

-- m

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