Re: Simplify with NestedLessLess?

*To*: mathgroup at smc.vnet.net*Subject*: [mg106533] Re: Simplify with NestedLessLess?*From*: Dave Bird <dbird at ieee.org>*Date*: Fri, 15 Jan 2010 03:21:32 -0500 (EST)*References*: <himsqd$jd0$1@smc.vnet.net> <4B4F126E.4010304@metrohm.com> <4B4FAB01.1080604@ieee.org> <4B50050F.6040706@metrohm.com>*Reply-to*: dbird at ieee.org

Thanks Daniel, I'll check it out. Dave dh wrote: > Hi Dave, > the simplest you can do is to use a user defined function. > If you want to define a infix operator, look at the docu of the > Notation package, but this is not a topic I would tackle as a beginner. > Daniel > > Dave Bird wrote: >> Thanks Daniel for the info. >> >> How does one "design a new operator" which Simplify could use as an >> assumption. I'm a Mathematica newby, so please excuse my ignorance. >> >> Thanks again, >> >> Dave >> >> dh wrote: >>> Hi Dave, >>> << does not have a meaning in mathematica. It is only a symbol. >>> Therefore your expression is not simplified. >>> You may define a new operator for your purposes. >>> Daniel >>> >>> dbird wrote: >>>> Please excuse if this has been answered before, but I can't find it. >>>> >>>> Is there some way to do a Simplify with assumptions using a >>>> NestedLessLess or something similar? For example: >>>> >>>> d=a+b >>>> Simplify[d,NestedLessLess[a,b]] >>>> >>>> Answer is: >>>> a+b >>>> >>>> Answer should be: >>>> b >>>> >>>> Thanks, >>>> >>>> Dave >>>> >>> >>> >>> >> >> >> > >