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Re: Simplify with NestedLessLess?

• To: mathgroup at smc.vnet.net
• Subject: [mg106533] Re: Simplify with NestedLessLess?
• From: Dave Bird <dbird at ieee.org>
• Date: Fri, 15 Jan 2010 03:21:32 -0500 (EST)
• References: <himsqd$jd0$1@smc.vnet.net> <4B4F126E.4010304@metrohm.com> <4B4FAB01.1080604@ieee.org> <4B50050F.6040706@metrohm.com>
• Reply-to: dbird at ieee.org

Thanks Daniel, I'll check it out.

Dave

dh wrote:
> Hi Dave,
> the simplest you can do is to use a user defined function.
> If you want to define a infix operator, look at the docu of the 
> Notation package, but this is not a topic I would tackle as a beginner.
> Daniel
>
> Dave Bird wrote:
>> Thanks Daniel for the info.
>>
>> How does one "design a new operator" which Simplify could use as an 
>> assumption. I'm a Mathematica newby, so please excuse my ignorance.
>>
>> Thanks again,
>>
>> Dave
>>
>> dh wrote:
>>> Hi Dave,
>>> << does not have a meaning in mathematica. It is only a symbol. 
>>> Therefore your expression is not simplified.
>>> You may define a new operator for your purposes.
>>> Daniel
>>>
>>> dbird wrote:
>>>> Please excuse if this has been answered before, but I can't find it.
>>>>
>>>> Is there some way to do a Simplify with assumptions using a 
>>>> NestedLessLess or something similar? For example:
>>>>
>>>> d=a+b
>>>> Simplify[d,NestedLessLess[a,b]]
>>>>
>>>> Answer is:
>>>> a+b
>>>>
>>>> Answer should be:
>>>> b
>>>>
>>>> Thanks,
>>>>
>>>> Dave
>>>>
>>>
>>>
>>>
>>
>>
>>
>
>