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Re: boolean variable with contours

  • To: mathgroup at
  • Subject: [mg110714] Re: boolean variable with contours
  • From: Peter Pein <petsie at>
  • Date: Sat, 3 Jul 2010 08:17:21 -0400 (EDT)
  • References: <>

Am Fri, 2 Jul 2010 06:54:31 +0000 (UTC)
schrieb maria giovanna dainotti <mariagiovannadainotti at>:

> Dear Math Group,
> I have the following problem when I do a contourplot I can't use
> the boolean variabile.  This is the function for which I would like
> to have the contours
> R1=1.029
> R2=2.92
> R3
> e1=300
> e2=1
> e3=100
> i=pi/12
> =C2 ContourPlot[]==0==Im[y,{x,-2,2 },{y,-20,20}]
> Thanks a lot for your help
> Maria

Hi Maria,

1.) pi is just any variable; I guess you want Pi (with capital P) and
the Re[] around  x/"real valued constant" is superfluous.
2.) what exactly do you expect from a call to Contourplot with three
expressions (not wrapped by a list). Did you want ParametricPlot3D
(which looks quite boring). Are the three expressions part of a vector
and you want the norm? That would lead to a few vertical stripes.
3.) It could speed thing up to throw FullSimplify once onto the
expression(s) to be plotted:
In[1]:= R1=1029/1000;

Out[8]= {200 Sqrt[400-x^2]+(299 Sqrt[1058841-1000000 x^2]-3960
Sqrt[5329-625 x^2])/(125 (Sqrt[2]+Sqrt[6])),4/25 (1250 Sqrt[400-x^2]-99
Sqrt[(-2+Sqrt[3]) (-5329+625 x^2)])
Sqrt[400-x^2] (Boole[25 x>73]+Boole[x<-(73/25)])}


P.S.: Claws-Mail opened this again; maybe I forgot to send it maybe
this posting comes twice. In the latter case: my apologies to the brave

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