Re: PDE, laplace, exact, should be simple...
- To: mathgroup at smc.vnet.net
- Subject: [mg110138] Re: PDE, laplace, exact, should be simple...
- From: Murray Eisenberg <murray at math.umass.edu>
- Date: Thu, 3 Jun 2010 05:40:49 -0400 (EDT)
You have a superfluous third = at the end of the first line of the
definition of BCs. And something got garbled in the message; is "=F0" a
version of some ASCII code?
I presume you meant there that u[x,1]==Sin[x].
If so, then obviously the alleged solution does not satisfy that last
boundary condition:
Sin[Pi x] Sinh[Pi y] /. y -> 1 // InputForm
Sin[Pi*x]*Sinh[Pi]
On 6/2/2010 2:05 AM, peter lindsay wrote:
> forgive the simplicity of this:
>
> D[u[x, y], {x, 2}] + D[u[x, y], {y, 2}] == 0
>
>
> BCs={u[0, y] == 0, u[x, 0] == 0, u[1, y] == 0, u[x, 1] ===
> Sin[=F0 x]}
>
>
> DSolve etc, etc, etc...
>
>
> A solution is Sin[Pi x] Sinh[Pi y]
>
>
> How can I get mathematica to come up with this gem ?
>
>
> thanks, and sorry again for any stupidity on my part
>
>
> Peter Lindsay
>
--
Murray Eisenberg murrayeisenberg at gmail.com
80 Fearing Street phone 413 549-1020 (H)
Amherst, MA 01002-1912