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Re: PDE, laplace, exact, should be simple...

  • To: mathgroup at smc.vnet.net
  • Subject: [mg110138] Re: PDE, laplace, exact, should be simple...
  • From: Murray Eisenberg <murray at math.umass.edu>
  • Date: Thu, 3 Jun 2010 05:40:49 -0400 (EDT)

You have a superfluous third = at the end of the first line of the 
definition of BCs.  And something got garbled in the message; is "=F0" a 
version of some ASCII code?

I presume you meant there that u[x,1]==Sin[x].

If so, then obviously the alleged solution does not satisfy that last 
boundary condition:

   Sin[Pi x] Sinh[Pi y] /. y -> 1 // InputForm
Sin[Pi*x]*Sinh[Pi]


On 6/2/2010 2:05 AM, peter lindsay wrote:
> forgive the simplicity of this:
>
> D[u[x, y], {x, 2}] + D[u[x, y], {y, 2}] == 0
>
>
> BCs={u[0, y] == 0, u[x, 0] == 0, u[1, y] == 0, u[x, 1] ===
>   Sin[=F0 x]}
>
>
> DSolve etc, etc, etc...
>
>
> A solution is Sin[Pi x] Sinh[Pi y]
>
>
> How can I get mathematica to come up with this gem ?
>
>
> thanks, and sorry again for any stupidity on my part
>
>
> Peter Lindsay
>

-- 
Murray Eisenberg                     murrayeisenberg at gmail.com
80 Fearing Street                    phone 413 549-1020 (H)
Amherst, MA 01002-1912


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