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Re: Efficient search for bounding list elements

  • To: mathgroup at smc.vnet.net
  • Subject: [mg114192] Re: Efficient search for bounding list elements
  • From: Alexei Boulbitch <alexei.boulbitch at iee.lu>
  • Date: Fri, 26 Nov 2010 05:31:01 -0500 (EST)

Hi, David,

this

searchFunction[x_, a_] := {Last@Select[a, #<  x&],
    First@Select[a, #>  x&]}

may give the answer you are looking for.
Let us try:
  
a = Range[1000, 5000, 250];
x = 1800;
searchFunction[x, a]


{1750, 2000}

Have fun, Alexei


I've been looking for a way to efficiently find the indices of the two
elements of a monotonically increasing list which bound a number.  For
example, if

a = Range[1000,5000,250]

and

x=1600

then I'd like this function (e.g., searchFunction[x,a]) to return
{3,4}, which correspond to the 3rd and 4th elements of a, which are
1500 and 1750, respectively.

I can easily do this in a loop, but in my application a can be very
large (hundreds of thousands or millions of elements) and this
operation needs to repeated thousands of times, so efficiency is
critical.

Any suggestions would be greatly appreciated!

Thanks,

David Skulsky

-- 
Alexei Boulbitch, Dr. habil.
Senior Scientist
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