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Re: Replacement Rule with Sqrt in denominator


On 11/20/2010 3:11 AM, kj wrote:

>
> I don't know a way to write the replacement rule so that it works
> for both Sqrt[x] and 1/Sqrt[x], but maybe someone else does.
>
> ~kj
>
See
www.cs.berkeley.edu/~fateman/papers/better-rules.pdf

which describes how one can automatically produce rules that overcome
this bug in Mathematica.  oops.  I mean rules that overcome this 
"feature" in Mathematica.

RJF



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