       Re: Can somebody integrate this function ?

• To: mathgroup at smc.vnet.net
• Subject: [mg112550] Re: Can somebody integrate this function ?
• From: "David Park" <djmpark at comcast.net>
• Date: Sun, 19 Sep 2010 05:40:18 -0400 (EDT)

```Works for me on Version 7.0.1. Suppressing the rather long answer:

f[z_] := 5/
12 (-1 + z) (y^2 - 3 z^2) (27 y^4 - 12 Sqrt y^5 + 4 y^6 +
18 y^2 (3 - 2 z) z^2 + 3 (3 - 2 z)^2 z^4 +
4 Sqrt y^3 z^2 (-3 + 2 z));

intgf[z_] = Integrate[f[z], z];

intgf'[z] == f[z] // Simplify

True

David Park
djmpark at comcast.net
http://home.comcast.net/~djmpark/

From: c r [mailto:riemannchristoffel at gmail.com]

Can somebody try this in your version of Mathematica ?

Integrate[(5/12) (-1 + z) (y^2 - 3 z^2) (27 y^4 - 12 Sqrt y^5 +
4 y^6 + 18 y^2 (3 - 2 z) z^2 + 3 (3 - 2 z)^2 z^4 +
4 Sqrt y^3 z^2 (-3 + 2 z)), z]

Something is definitely wrong with my version of Mathematica (7).

```

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