Re: solution
- To: mathgroup at smc.vnet.net
- Subject: [mg118284] Re: solution
- From: "Sjoerd C. de Vries" <sjoerd.c.devries at gmail.com>
- Date: Wed, 20 Apr 2011 04:27:40 -0400 (EDT)
- References: <iojpp7$i52$1@smc.vnet.net>
Why don't you increase the number of starting values? With 100 the number of unique solutions found by Mathematica is 42 (a magic number in certain circles). If you take 260 instead you'll get 100 roots. Cheers -- Sjoerd Fast responses to Mathematica questions at StackOverflow http://stackoverflow.com/questions/tagged/mathematica On Apr 19, 12:56 pm, amelia Jackson <meli.jac... at gmail.com> wrote: > Dear MathGroup, > > I have a problem. I want to find solution: > r := Table[ > k /. FindRoot[BesselJ[0, k] + k BesselJ[1, k] == 0, {k, n}], {n, 1, 100}] > > but I get about 30 roots. I need about 100 or more. > I think that "step" "n" tend to Pi > > Please for help...