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Limit[f[x], x->a] vs. f[a]. When are they equal?

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  • Subject: [mg118338] Limit[f[x], x->a] vs. f[a]. When are they equal?
  • From: Richard Fateman <fateman at cs.berkeley.edu>
  • Date: Sat, 23 Apr 2011 07:49:28 -0400 (EDT)

Let c=ComplexInfinity

then Mathematica (7.0) "knows" that Sin[c] is Indeterminate

but Limit[Sin[x],x->c]  is not evaluated.

I would have thought that if  f[a] is known, Limit[f[x],x->a] is
also known.

RJF


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