Limit[f[x], x->a] vs. f[a]. When are they equal?
- To: mathgroup at smc.vnet.net
- Subject: [mg118338] Limit[f[x], x->a] vs. f[a]. When are they equal?
- From: Richard Fateman <fateman at cs.berkeley.edu>
- Date: Sat, 23 Apr 2011 07:49:28 -0400 (EDT)
Let c=ComplexInfinity then Mathematica (7.0) "knows" that Sin[c] is Indeterminate but Limit[Sin[x],x->c] is not evaluated. I would have thought that if f[a] is known, Limit[f[x],x->a] is also known. RJF