MathGroup Archive: December 2011 [00307]

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Re: Inverse Function

To: mathgroup at smc.vnet.net
Subject: [mg123618] Re: Inverse Function
From: Bob Hanlon <hanlonr357 at gmail.com>
Date: Tue, 13 Dec 2011 05:42:00 -0500 (EST)
Delivered-to: l-mathgroup@mail-archive0.wolfram.com
References: <201112121143.GAA12844@smc.vnet.net>

f[x_] = (a*x + b)/(c*x + d);

x /. Solve[y == f[x], x][[1]]

(-b + d*y)/(a - c*y)

InverseFunction[f][y]

(-b + d*y)/(a - c*y)

f[InverseFunction[f][y]] // Simplify

y

InverseFunction[f][f[x]] // Simplify

x


Bob Hanlon


On Mon, Dec 12, 2011 at 6:43 AM, Harry Har <harryhar800 at gmail.com> wrote:
> Hi, All,
>
> I'm newbie in Mathematica. I want to find the inverse function of y=(ax
> +b)/(cx+d). How to to this in Mathematica? Many thank's.
>
> Harry.
>

References:
- Inverse Function
  - From: Harry Har <harryhar800@gmail.com>

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