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Re: Inverse Function

  • To: mathgroup at smc.vnet.net
  • Subject: [mg123609] Re: Inverse Function
  • From: DrMajorBob <btreat1 at austin.rr.com>
  • Date: Tue, 13 Dec 2011 05:40:14 -0500 (EST)
  • Delivered-to: l-mathgroup@mail-archive0.wolfram.com
  • References: <201112121143.GAA12844@smc.vnet.net>
  • Reply-to: drmajorbob at yahoo.com

You realize your equation has precisely THESE variables?

{y, (ax + b)/(cx + d)} // Variables

{ax, b, cx, d, y}

x is not one of them, as you see.

I'll assume you meant

y == (a x + b)/(c x + d);
Solve[%, x]

{{x -> (-b + d y)/(a - c y)}}

Bobby

On Mon, 12 Dec 2011 05:43:50 -0600, Harry Har <harryhar800 at gmail.com>  
wrote:

> Hi, All,
>
> I'm newbie in Mathematica. I want to find the inverse function of y=(ax
> +b)/(cx+d). How to to this in Mathematica? Many thank's.
>
> Harry.
>


-- 
DrMajorBob at yahoo.com



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