Re: Inverse Function
- To: mathgroup at smc.vnet.net
- Subject: [mg123609] Re: Inverse Function
- From: DrMajorBob <btreat1 at austin.rr.com>
- Date: Tue, 13 Dec 2011 05:40:14 -0500 (EST)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- References: <201112121143.GAA12844@smc.vnet.net>
- Reply-to: drmajorbob at yahoo.com
You realize your equation has precisely THESE variables? {y, (ax + b)/(cx + d)} // Variables {ax, b, cx, d, y} x is not one of them, as you see. I'll assume you meant y == (a x + b)/(c x + d); Solve[%, x] {{x -> (-b + d y)/(a - c y)}} Bobby On Mon, 12 Dec 2011 05:43:50 -0600, Harry Har <harryhar800 at gmail.com> wrote: > Hi, All, > > I'm newbie in Mathematica. I want to find the inverse function of y=(ax > +b)/(cx+d). How to to this in Mathematica? Many thank's. > > Harry. > -- DrMajorBob at yahoo.com
- References:
- Inverse Function
- From: Harry Har <harryhar800@gmail.com>
- Inverse Function