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Re: factoring


On Dec 30 2010, 7:07 pm, DrMajorBob <btre... at austin.rr.com> wrote:
> It fails because the variables x, y, and z do not appear in the original 
> expression. (It involves only the three variables xy, xz, and yz.)
>
> This works, however:
>
> Factor[x y - x z + y^2 - y z]
>
> (x + y) (y - z)
>
> Bobby
>
> On Thu, 30 Dec 2010 03:09:17 -0600, r_poetic <radford.scha... at mms.gov> 
> wrote:
>
> > Hello,
> > an easy question:
>
> > why does Factor[xy-xz+y^2-yz] fail to return (x+y)(y-z), and what
> > command would do that?
>
> > Thanks!
>
> --
> DrMajor... at yahoo.com

Thanks for both responses!
RS


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