       • To: mathgroup at smc.vnet.net
• From: Andrzej Kozlowski <akoz at mimuw.edu.pl>
• Date: Tue, 4 Jan 2011 04:28:37 -0500 (EST)
• References: <ifs30a\$oor\$1@smc.vnet.net> <4D21F917.2020209@cs.berkeley.edu> <48AEFA8B-880D-4B9A-B9CC-C1C7414D1384@mimuw.edu.pl> <A934FC78-8B93-45FB-A48D-D5BE2606760E@mimuw.edu.pl> <4D2254B8.8080703@eecs.berkeley.edu>

```On 3 Jan 2011, at 23:59, Richard Fateman wrote:

> On 1/3/2011 12:28 PM, Andrzej Kozlowski wrote:
>>
>> I forgot one obvious matter. A better way to solve this problem is:
>>
>> quadp[f_, x_] /; PolynomialQ[f, x]&&  Exponent[f, x] == 2 :=
>>  qq @@ CoefficientList[f, x]
>>
>> quadp[5 + 4*x + 3*x^2, x]
>>
>> qq(5,4,3)
>>
>>
>> qq(0,0,r+s)
>
> yours does not work for quadp[(x^3+x)/x, x], which I think is a quadratic.
> my program agrees with me.
>

If you are going to include non-explcit polynomials than of course you need to use Simplify. Try your program on, for example,  (Sin[x]^2 + Cos[x]^2) x  or lots of other expressions of this kind. This is a "polynomial" as much as (x^3+x)/x is.

Andrzej Kozlowski

```

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