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Re: Solving 2nd order PDE into Mathematica


What are the initial conditions?

Bobby

On Wed, 05 Jan 2011 04:48:20 -0600, tarpanelli at libero.it  
<tarpanelli at libero.it> wrote:

> Hello,
>
> I saw that DSolve can not solve a 2nd order pde like this
>
> pde=-D[f[x,t],x]+D[f[x,t],{x,2}]==D[f[x,t],t]
>
> but I would like to know if someone has already implemented some other
> procedure to solve it
>
> Thank you in advance
> Paolo
>


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