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Re: Solving 2nd order PDE into Mathematica

  • To: mathgroup at smc.vnet.net
  • Subject: [mg115280] Re: Solving 2nd order PDE into Mathematica
  • From: "tarpanelli at libero.it" <tarpanelli at libero.it>
  • Date: Thu, 6 Jan 2011 02:05:07 -0500 (EST)

The initial condition is 

f(x,0)=delta(x-x(0))

where delta is the dirac delta function

P

>----Messaggio originale----
>Da: btreat1 at austin.rr.com
>Data: 05/01/2011 20.48
>A: <mathgroup at smc.vnet.net>, "tarpanelli at libero.it"<tarpanelli at libero.it>
>Ogg: Re: [mg115259] Solving 2nd order PDE into Mathematica
>
>What are the initial conditions?
>
>Bobby
>
>On Wed, 05 Jan 2011 04:48:20 -0600, tarpanelli at libero.it  
><tarpanelli at libero.it> wrote:
>
>> Hello,
>>
>> I saw that DSolve can not solve a 2nd order pde like this
>>
>> pde=-D[f[x,t],x]+D[f[x,t],{x,2}]==D[f[x,t],t]
>>
>> but I would like to know if someone has already implemented some other
>> procedure to solve it
>>
>> Thank you in advance
>> Paolo
>>
>
>
>-- 
>DrMajorBob at yahoo.com
>




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