Re: Solving 2nd order PDE into Mathematica

*To*: mathgroup at smc.vnet.net*Subject*: [mg115280] Re: Solving 2nd order PDE into Mathematica*From*: "tarpanelli at libero.it" <tarpanelli at libero.it>*Date*: Thu, 6 Jan 2011 02:05:07 -0500 (EST)

The initial condition is f(x,0)=delta(x-x(0)) where delta is the dirac delta function P >----Messaggio originale---- >Da: btreat1 at austin.rr.com >Data: 05/01/2011 20.48 >A: <mathgroup at smc.vnet.net>, "tarpanelli at libero.it"<tarpanelli at libero.it> >Ogg: Re: [mg115259] Solving 2nd order PDE into Mathematica > >What are the initial conditions? > >Bobby > >On Wed, 05 Jan 2011 04:48:20 -0600, tarpanelli at libero.it ><tarpanelli at libero.it> wrote: > >> Hello, >> >> I saw that DSolve can not solve a 2nd order pde like this >> >> pde=-D[f[x,t],x]+D[f[x,t],{x,2}]==D[f[x,t],t] >> >> but I would like to know if someone has already implemented some other >> procedure to solve it >> >> Thank you in advance >> Paolo >> > > >-- >DrMajorBob at yahoo.com >