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Re: Evaluation of limit

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  • Subject: [mg115738] Re: Evaluation of limit
  • From: Bill Rowe <readnews at>
  • Date: Wed, 19 Jan 2011 05:29:53 -0500 (EST)

On 1/18/11 at 5:52 AM, jogc at (Dr. C. S. Jog) wrote:

>If I give the command
>In[1]:= Limit[Cosh[x]+Sinh[x]^2*Log[Tanh[x/2]],x->Infinity]

>I get
>x          2
>Out[1]= Limit[Cosh[x] + Log[Tanh[-]] Sinh[x] , x -> Infinity]

>instead of zero. This result can be verified numerically (of course,
>by using higher precision than the default).

I get

In[1]:= Limit[Cosh[x] + Sinh[x]^2*Log[Tanh[x/2]], x -> Infinity]

Out[1]= 0

In[2]:= $Version

Out[2]= 8.0 for Mac OS X x86 (64-bit) (November 6, 2010)

What version of Mathematica are you using?

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