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Re: Vector problem
*To*: mathgroup at smc.vnet.net
*Subject*: [mg115959] Re: Vector problem
*From*: m.perrin at me.com
*Date*: Thu, 27 Jan 2011 03:41:50 -0500 (EST)
The Mathematica part of the problem was that Projection could be included in the Solve function. I wasn't aware that Solve could take that input
Solve [ {Projection[ {x,y} , v ] == v, Projection[ {x,y} , u ] == u}, {x,y}]
(* where {x,y} is unknown vector z, and u and v are the known 2D vectors ; spaces are for clarity*)
But as I posted, I solved the problem (no pun intended).
On Jan 26, 2011, at 05:07 AM, Murray Eisenberg <murray at math.umass.edu> wrote:
This doesn't at all sound like a Mathematica problem, but rather like a
mathematics problem.
On 1/25/2011 4:19 AM, Mark Perrin wrote:
> I'm having trouble formulating a problem in Mathematica.
>
> If I have two 2D vectors, u and v that are the known projections of a third unknown 2D vector z, how do I determine z?
>
> My word problem (I think) is find the solution to: Projection[z,u] == u&& Projection [z,v] == v
>
> Any help in starting this problem would be much appreciated.
>
>
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