       Re: How can I get better solution for this...?

• To: mathgroup at smc.vnet.net
• Subject: [mg120054] Re: How can I get better solution for this...?
• From: Siddharth Srivastava <siddys at gmail.com>
• Date: Thu, 7 Jul 2011 07:30:23 -0400 (EDT)
• References: <201107060939.FAA29377@smc.vnet.net>

```Hi Bobby,
Thanks for the quick reply. What I am trying to do is to get an
analytical form for
the decomposition of an Affine transformation matrix into scale (sx sy) and
shear
(gx gy) components. Maybe if you have an alternative way to get this, that
would
Thanks,
#

On Wed, Jul 6, 2011 at 10:36 AM, DrMajorBob <btreat1 at austin.rr.com> wrote:

> Ah yes... I misread your post in the heat of the moment.
>
> The first three equations determine sy, gx, and gy in terms of p00, p01,
> p11, and sx:
>
> soln = Quiet@
>
>   Solve[{sx^2 (1 + gx gy)^2 + sx^2 gy^2 == p00,
>     sx sy gx (1 + gx gy) + sx sy gy == p01,
>     sy^2 (1 + gx^2) == p11}, {sx, sy, gx, gy}];
> soln[[All, All, 1]]
>
> {{sy, gx, gy}, {sy, gx, gy}, {sy, gx, gy}, {sy, gx, gy}}
>
> giving four solutions. If the fourth equation is also true, each of these
> solutions determines a value for d:
>
> Solve[sx sy == d, d] /. soln
>
> (four solutions)
>
> Hence, your four equations have no solution with d free to vary.
>
>
> Solve[{sx^2 (1 + gx gy)^2 + sx^2 gy^2 == p00,
>  sx sy gx (1 + gx gy) + sx sy gy == p01, sy^2 (1 + gx^2) == p11,
>  sx sy == d}, {gx}]
>
> {}
>
> Bobby
>
>
> On Wed, 06 Jul 2011 11:50:17 -0500, Siddharth Srivastava <siddys at gmail.com>
> wrote:
>
>  Hi Bobby,
>>    Thanks. I actually wanted sx, sy, gx and gy in terms of the P coeff.
>> The
>> solution
>> you gave is just the equation that I wanted to solve!
>> #
>>
>> On Wed, Jul 6, 2011 at 9:18 AM, DrMajorBob <btreat1 at austin.rr.com> wrote:
>>
>>  Solve[{sx^2 (1 + gx gy)^2 + sx^2 gy^2 == p00,
>>>  sx sy gx (1 + gx gy) + sx sy gy == p01, sy^2 (1 + gx^2) == p11,
>>>  sx sy == d}, {p00, p01, p11, d}]
>>>
>>> {{p00 -> sx^2 + 2 gx gy sx^2 + gy^2 sx^2 + gx^2 gy^2 sx^2,
>>>  p01 -> gx sx sy + gy sx sy + gx^2 gy sx sy, p11 -> (1 + gx^2) sy^2,
>>>  d -> sx sy}}
>>>
>>> Bobby
>>>
>>> On Wed, 06 Jul 2011 04:39:55 -0500, sid <siddys at gmail.com> wrote:
>>>
>>>  Hi all,
>>>
>>>>   I am trying to solve the following for {sx,sy,gx,gy}
>>>>
>>>>    sx^2 (1 + gx gy)^2 + sx^2 gy^2 = P00 ........(1)
>>>>    sx sy gx (1 + gx gy) + sx sy gy = P01 .......(2)
>>>>    sy^2 ( 1 + gx^2) = P11 ..............................****.(3)
>>>>    sx sy  = D ..............................****..................(4)
>>>>
>>>> in terms of P00,P01,P11, and D.
>>>>
>>>> When I use Solve[] , I get a huge output containing the P terms up
>>>> till the order of 16 (i.e P00^16 etc..), which
>>>> I know is not correct. I do not think I am specifying the problem
>>>> correctly, and being a non-expert in Mathematica, would appreciate
>>>> some help. Specifically
>>>> 1) should I specify the simultaneous equation using && operator? I
>>>> have tried it, and I get different (but huge) output
>>>> 2) can I break the problem into parts? how?
>>>> Thanks,
>>>> s.
>>>>
>>>>
>>>>
>>> --
>>> DrMajorBob at yahoo.com
>>>
>>>
>
> --
> DrMajorBob at yahoo.com
>

```

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