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Re: querries

  • To: mathgroup at
  • Subject: [mg119560] Re: querries
  • From: "Dr. Wolfgang Hintze" <weh at>
  • Date: Fri, 10 Jun 2011 06:37:43 -0400 (EDT)
  • References: <isq4o1$63f$>

You need to tell Mathematica something about mu and lambda in order to 
make the expressions unambigious.
Then it works out fine.


Simplify[(mu*lambda)^(b) - (mu^b)*(lambda^b), {mu > 0, lambda > 0}]


"Savits, Thomas H" <savits at> schrieb im Newsbeitrag 
news:isq4o1$63f$1 at
> 1)       Why does Mathematica not give the value 0 to the expression
> (mu*lambda)^(b) - (mu^b)*(lambda^b)? It seems to treat the expression 
> (mu*lambda) as a new variable. I used the greek letters from the 
> palette in the actual expression.
> 2)       Many times I cannot get Mathematica to simplify expressions 
> involving the exponential functions, e.g., it won't combine the 
> arguments of the Exp functions. Is there a way to force this?
> Thanks,
> Tom Savits
> Statistics Department
> University of Pittsburgh 

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