- To: mathgroup at smc.vnet.net
- Subject: [mg119571] Re: querries
- From: Alexei Boulbitch <alexei.boulbitch at iee.lu>
- Date: Fri, 10 Jun 2011 06:39:42 -0400 (EDT)
Concerning your first question, try this: (mu*lambda)^(b) - (mu^b)*(lambda^b) // PowerExpand 0 Concerning the second one, it is not quite clear, what do you have in mind, since this: Exp[a]*Exp[b] E^(a + b) works. You have probably a more complex example in mind. Have fun, Alexei 1) Why does Mathematica not give the value 0 to the expression (mu*lambda)^(b) - (mu^b)*(lambda^b)? It seems to treat the expression (mu*lambda) as a new variable. I used the greek letters from the palette in the actual expression. 2) Many times I cannot get Mathematica to simplify expressions involving the exponential functions, e.g., it won't combine the arguments of the Exp functions. Is there a way to force this? Thanks, Tom Savits Statistics Department University of Pittsburgh -- Alexei Boulbitch, Dr. habil. Senior Scientist Material Development IEE S.A. ZAE Weiergewan 11, rue Edmond Reuter L-5326 CONTERN Luxembourg Tel: +352 2454 2566 Fax: +352 2454 3566 Mobile: +49 (0) 151 52 40 66 44 e-mail: alexei.boulbitch at iee.lu www.iee.lu -- This e-mail may contain trade secrets or privileged, undisclosed or otherwise confidential information. If you are not the intended recipient and have received this e-mail in error, you are hereby notified that any review, copying or distribution of it is strictly prohibited. Please inform us immediately and destroy the original transmittal from your system. Thank you for your co-operation.