Re: About C[i]
- To: mathgroup at smc.vnet.net
- Subject: [mg117694] Re: About C[i]
- From: Peter <petsie at dordos.net>
- Date: Wed, 30 Mar 2011 04:08:33 -0500 (EST)
- References: <imshf8$5r8$1@smc.vnet.net>
Am 29.03.2011 13:57, schrieb olfa: > Hi Mathematica community, > > I have this solution set: > ((C[1] | C[2]) \[Element] Integers&& i == C[2]&& k == 7 C[1]&& > kP == 0&& iP == C[1] + C[2]) ||((C[1] | C[2]) \[Element] Integers > && > i == C[2]&& k == 2 + 7 C[1]&& kP == 2&& iP == C[1] + C[2]) > > it means that it is an infinite solution set. > I need to expess it without C[1] and C[2] since C[1]==k/7||(k-2)/7 > and C[2]==i . consequently the solution set would be expressed as > (kP==0&& iP==k/7+i)||(kP==2&&iP==(k-2)/7+i) > is it possible? how?can we say that is now transformed into finite > set? > > thank you very much for your help. > Ooops, I forgot: did you try the Option "Backsubstitution->True" in your call to Reduce?