• To: mathgroup at smc.vnet.net
• Subject: [mg117694] Re: About C[i]
• From: Peter <petsie at dordos.net>
• Date: Wed, 30 Mar 2011 04:08:33 -0500 (EST)
• References: <imshf8\$5r8\$1@smc.vnet.net>

Am 29.03.2011 13:57, schrieb olfa:
> Hi Mathematica community,
>
> I have this solution set:
> ((C[1] | C[2]) \[Element] Integers&&  i == C[2]&&  k == 7 C[1]&&
>     kP == 0&&  iP == C[1] + C[2]) ||((C[1] | C[2]) \[Element] Integers
> &&
>   i == C[2]&&  k == 2 + 7 C[1]&&    kP == 2&&  iP == C[1] + C[2])
>
> it means that it is an infinite solution set.
> I need to expess it without C[1] and C[2] since C[1]==k/7||(k-2)/7
> and C[2]==i . consequently the solution set would be expressed as
> (kP==0&&  iP==k/7+i)||(kP==2&&iP==(k-2)/7+i)
>   is it possible? how?can we say that is now transformed into finite
> set?
>
> thank you very much for your help.
>

Ooops, I forgot:

did you try the Option "Backsubstitution->True" in your call to Reduce?

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