Re: How to do quickest
- To: mathgroup at smc.vnet.net
- Subject: [mg123091] Re: How to do quickest
- From: Artur <grafix at csl.pl>
- Date: Wed, 23 Nov 2011 07:05:32 -0500 (EST)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- References: <201111210929.EAA14830@smc.vnet.net> <8FECCEBE-CBFE-4B7C-87A5-4856C65C2DB4@mimuw.edu.pl> <7F85110E-2F9F-4B87-8F98-C7EEF63DEB4D@mimuw.edu.pl> <201111221223.HAA00196@smc.vnet.net> <sig.13073ac2f6.4ECBD594.7060709@csl.pl> <5E76C41D-6FD7-4FFD-B1D2-979439064056@mimuw.edu.pl> <5135FED0-49ED-4978-9FCE-B13734E59C8D@mimuw.edu.pl>
- Reply-to: grafix at csl.pl
Dear Andrzej,
>I am not sure if adding this will speed up the code. I only have one copy of Mathematica and I need to use>it so I can't afford the time to run these programs now, when I am a hurry.
I will check them exactly soon and let You know. Thank You for idea but we can add few more before we will start timme expensive routines with polynomials e.g. all x of the form 4^i (8x+7) (where i is highest power of 4 dividing x) have to be case that polynomial of 12 degree is irreducible.
Best wishes
Artur
W dniu 2011-11-22 19:40, Andrzej Kozlowski pisze:
> I think the correct use of Eisenstein's criterion is this:
>
>
> Block[{y = Round[Sqrt[x^3]]},
> Reap[Table[
> If[x^3 - y^2 != 0&&
> Not[Mod[x^6 - 2*x^3*y^2 + y^4, 2] == 0&&
> Mod[x^6 - 2*x^3*y^2 + y^4, 4] != 0]&& !
> IrreduciblePolynomialQ[poly], Sow[{x, y}]], {x, 2,
> 1000000}]][[2]]] // Timing
>
> This is because 3645 is not divisible by 2, but 2916 and 270 both are. So if the term x^6-2 x^3 y^2+y^4 is divisible by 2 but not divisible by 4, the polynomial is irreducible and there is no need to test it further. Only when this isn't the case, we need to use IrreduciblePolynomialQ.
>
> I am not sure if adding this will speed up the code. I only have one copy of Mathematica and I need to use it so I can't afford the time to run these programs now, when I am a hurry.
>
> Andrzej
>
>
>
> On 22 Nov 2011, at 19:30, Andrzej Kozlowski wrote:
>
>> My memory of Eisenstein's criterion was wrong (also, I was too much in a hurry to look it up). Rather than correcting it I got rid of it altogether since I think Mathematica probably uses it anyway. I then get:
>>
>> In[1]:= Collect[
>> poly = Eliminate[{4*m^2 + 6*m*n + n^2 ==
>> x, (19*m^2 + 9*m*n + n^2)*Sqrt[m^2 + n^2] == y}, {n}] /.
>> Equal -> Subtract, m]
>>
>> Out[1]= 3645 m^12-2916 m^10 x+m^6 (270 x^3-270 y^2)+x^6-2 x^3 y^2+y^4
>>
>> In[2]:= Block[{y = Round[Sqrt[x^3]]},
>> Reap[Table[
>> If[x^3 - y^2 != 0&& Not[IrreduciblePolynomialQ[poly]],
>> Sow[{x, y}]], {x, 2, 1000000}]][[2]]] // Timing
>>
>>
>> Out[2]= {1089.54,({1942,85580} {2878,154396} {3862,240004} {6100,476425} {8380,767125} {11512,1235168} {15448,1920032} {18694,2555956} {31228,5518439} {93844,28748141} {111382,37172564} {117118,40080716} {129910,46823500} {143950,54615700} {186145,80311375} {210025,96251275} {375376,229985128} {445528,297380512} {468472,320645728} {575800,436925600} {844596,776199807} {950026,925983476}
>>
>> )}
>>
>> This gets all the numbers but is much slower (I guess it will be better to add the Eisenstein criterion after all, but of course, in correct form).
>>
>> Andrzej Kozlowski
>>
>>
>>
>>
>> On 22 Nov 2011, at 18:02, Artur wrote:
>>
>>> Dear Andrzej,
>>> Your procedure omiited some points
>>> 6100
>>> 8380 Best wishes
>>> Artur
>>>
>>> W dniu 2011-11-22 13:23, Andrzej Kozlowski pisze:
>>>> On 22 Nov 2011, at 10:07, Andrzej Kozlowski wrote:
>>>>
>>>>
>>>>> On 22 Nov 2011, at 10:06, Andrzej Kozlowski wrote:
>>>>>
>>>>>
>>>>>> On 21 Nov 2011, at 10:29, Artur wrote:
>>>>>>
>>>>>>
>>>>>>> Dear Mathematica Gurus,
>>>>>>> How to do quickest following procedure (which is very slowly):
>>>>>>>
>>>>>>> qq = {}; Do[y = Round[Sqrt[x^3]];
>>>>>>> If[(x^3 - y^2) != 0,
>>>>>>> kk = m /. Solve[{4 m^2 + 6 m n + n^2 ==
>>>>>>> x, (19 m^2 + 9 m n + n^2) Sqrt[m^2 + n^2] == y}, {m, n}][[1]];
>>>>>>> ll = CoefficientList[MinimalPolynomial[kk][[1]], #1];
>>>>>>> lll = Length[ll];
>>>>>>> If[lll< 12, Print[{x/(x^3 - y^2)^2, kk, x, y, x^3 - y^2}];
>>>>>>> If[Length[ll] == 3, Print[{kk, x, y}]]]], {x, 2, 1000000}];
>>>>>>> qq
>>>>>>>
>>>>>>>
>>>>>>> (*Best wishes Artur*)
>>>>>>>
>>>>>>>
>>>>>> I think it would be better to send not only the code but also the mathematical problem, as there may be a way to do it in a different way. Unless I am misunderstanding something, what you are trying to do is the same as this:
>>>>>>
>>>>>> In[31]:= Block[{y = Round[Sqrt[x^3]]},
>>>>>> Reap[Table[
>>>>>> If[(x^3 - y^2) != 0&& Not[IrreduciblePolynomialQ[poly]],
>>>>>> Sow[{x, y}]], {x, 2, 1000000}]][[2]]] // Timing
>>>>>>
>>>>>> Out[31]= {721.327,{}}
>>>>>>
>>>>>> This ought to be a lot faster than your code, but I have not tried to run yours to the end. Also, it is possible that using the Eisenstein Test explicitly may be somewhat faster:
>>>>>>
>>>>>> Block[{y = Round[Sqrt[x^3]]},
>>>>>> Reap[Table[
>>>>>> If[x^3 - y^2 != 0&& Mod[x^6 - 2*x^3*y^2 + y^4, 4] == 0&&
>>>>>> ! IrreduciblePolynomialQ[poly], Sow[{x, y}]], {x, 2,
>>>>>> 1000000}]][[2]]]
>>>>>>
>>>>>> {}
>>>>>>
>>>>>> but I forgot to use Timing and don't want to wait again, particularly that the answer is the empty set.
>>>>>>
>>>>>> Andrzej Kozlowski
>>>>>>
>>>>> I forgot to include the definition of poly:
>>>>>
>>>>> Collect[poly = Eliminate[{4*m^2 + 6*m*n + n^2 == x,
>>>>> (19*m^2 + 9*m*n + n^2)*Sqrt[m^2 + n^2] == y}, {n}] /. Equal -> Subtract, m]
>>>>>
>>>>> 3645*m^12 - 2916*m^10*x + m^6*(270*x^3 - 270*y^2) + x^6 -
>>>>> 2*x^3*y^2 + y^4
>>>>>
>>>>> Andrzej Kozlowski
>>>>>
>>>> Strange but I run this code with a fresh kernel and got the following answers:
>>>>
>>>> In[1]:= Collect[poly=Eliminate[{4*m^2+6*m*n+n^2==x,(19*m^2+9*m*n+n^2)*Sqrt[m^2+n^2]==y},{n}]/.Equal->Subtract,m]
>>>> Out[1]= 3645 m^12-2916 m^10 x+m^6 (270 x^3-270 y^2)+x^6-2 x^3 y^2+y^4
>>>>
>>>> In[2]:= Block[{y=Round[Sqrt[x^3]]},Reap[Table[If[x^3-y^2!=0&&Mod[x^6-2*x^3*y^2+y^4,4]==0&&!IrreduciblePolynomialQ[poly],Sow[{x,y}]],{x,2,1000000}]][[2]]]//Timing
>>>>
>>>> Out[2]= {766.05,({1942,85580} {2878,154396} {3862,240004} {11512,1235168} {15448,1920032} {18694,2555956} {111382,37172564} {117118,40080716} {129910,46823500} {143950,54615700} {186145,80311375} {210025,96251275} {375376,229985128} {445528,297380512} {468472,320645728} {575800,436925600} {950026,925983476}
>>>>
>>>> )}
>>>>
>>>>
>>>> I tested the first one and it does seem to be a solution to your problem.
>>>>
>>>> {x, y} = {950026, 925983476};
>>>>
>>>> y == Round[Sqrt[x^3]]
>>>>
>>>> True
>>>>
>>>> x^3 - y^2 != 0
>>>>
>>>> True
>>>>
>>>> kk =
>>>> m /. Solve[{4 m^2 + 6 m n + n^2 ==
>>>> x, (19 m^2 + 9 m n + n^2) Sqrt[m^2 + n^2] == y}, {m, n}][[1]]
>>>>
>>>> Out[12]= -Sqrt[-(198/5)-(44 I Sqrt[11])/5]
>>>>
>>>> ll = CoefficientList[MinimalPolynomial[kk][[1]], #1];
>>>>
>>>> Length[ll]
>>>>
>>>> 5
>>>>
>>>> I don't know why I got no answers the first time round, perhaps one of the variables had values assigned.
>>>>
>>>> Andrzej
>>>>
>>>>
>>>>
>>>>
>
- References:
- How to do quickest
- From: Artur <grafix@csl.pl>
- Re: How to do quickest
- From: Andrzej Kozlowski <akoz@mimuw.edu.pl>
- How to do quickest