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Re: Problem with Patterns and Integrate
*To*: mathgroup at smc.vnet.net
*Subject*: [mg123252] Re: Problem with Patterns and Integrate
*From*: Bill Rowe <readnews at sbcglobal.net>
*Date*: Tue, 29 Nov 2011 07:04:40 -0500 (EST)
*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com
On 11/28/11 at 5:53 AM, ejmcinerney at gmail.com (Jack McInerney) wrote:
>There is something about using patterns that I don't understand, and
>am hoping someone can shed some light. Here is an example of my
>problem. Say I have a function f[x] and I take the derivative of
>it. I can then integrate it and get f[x] back:
>In[167]:= expr = D[ f[x], x ] Out[167]= f=E2=80=B2[x]
>In[168]:= Integrate[expr, x] Out[168]= f[x]
>If I use a ReplaceAll and a pattern to do the integration, the
>Integrate function treats f'[x] as a constant and returns the wrong
>answer:
>In[169]:= expr /. func_ -> Integrate[func,x] Out[169]= x
>f=E2=80=B2[x]
>Any thoughts as to what I am doing wrong?
Yes, for this application you need to use RuleDelayed (:>)
instead of what you did. The key is when the rule is evaluated.
When you use -> the Integrate[func,x] is evaluated immediately
to func x and the replacement rule is equivalent to func_->func x.
Instead, if you use RuleDelayed (:>) evaluation of
Integrate[func,x] takes place after f'[x] is substituted for
func and you get the result you were looking for.
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