MathGroup Archive 2011

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: Cancel order

  • To: mathgroup at smc.vnet.net
  • Subject: [mg123273] Re: Cancel order
  • From: Bob Hanlon <hanlonr357 at gmail.com>
  • Date: Wed, 30 Nov 2011 03:19:22 -0500 (EST)
  • Delivered-to: l-mathgroup@mail-archive0.wolfram.com
  • References: <201111291205.HAA05469@smc.vnet.net>

expr = Sqrt[(v1^2 + v2^2) (g^2 + gp^2)]/Sqrt[v1^2 + v2^2];

Specify your assumptions to Simplify

Simplify[expr, Element[{v1, v2}, Reals]]

Sqrt[g^2 + gp^2]

Or use PowerExpand that defaults to a maximal set of assumptions

expr // PowerExpand

Sqrt[g^2 + gp^2]


Bob Hanlon


On Tue, Nov 29, 2011 at 7:05 AM, =E9=81=93 =E5=8E=9A <shlwell1988 at gmail.com> wrote:
> How can I make Sqrt[(v1^2+v2^2)(g^2+gp^2)]/Sqrt[v1^2+v2^2] simple in
> mathematica?
>



  • References:
  • Prev by Date: Re: How to simplify ArcSin formula
  • Next by Date: Re: Laplace equation with gradient boundary conditions
  • Previous by thread: Re: Cancel order
  • Next by thread: Re: Cancel order