Re: Cancel order
- To: mathgroup at smc.vnet.net
- Subject: [mg123273] Re: Cancel order
- From: Bob Hanlon <hanlonr357 at gmail.com>
- Date: Wed, 30 Nov 2011 03:19:22 -0500 (EST)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- References: <201111291205.HAA05469@smc.vnet.net>
expr = Sqrt[(v1^2 + v2^2) (g^2 + gp^2)]/Sqrt[v1^2 + v2^2]; Specify your assumptions to Simplify Simplify[expr, Element[{v1, v2}, Reals]] Sqrt[g^2 + gp^2] Or use PowerExpand that defaults to a maximal set of assumptions expr // PowerExpand Sqrt[g^2 + gp^2] Bob Hanlon On Tue, Nov 29, 2011 at 7:05 AM, =E9=81=93 =E5=8E=9A <shlwell1988 at gmail.com> wrote: > How can I make Sqrt[(v1^2+v2^2)(g^2+gp^2)]/Sqrt[v1^2+v2^2] simple in > mathematica? >
- References:
- Cancel order
- From: é å <shlwell1988@gmail.com>
- Cancel order