Re: count zeros in a number -> Clip[x] = ?

• To: mathgroup at smc.vnet.net
• Subject: [mg121909] Re: count zeros in a number -> Clip[x] = ?
• From: "Dr. Wolfgang Hintze" <weh at snafu.de>
• Date: Thu, 6 Oct 2011 04:23:42 -0400 (EDT)
• Delivered-to: l-mathgroup@mail-archive0.wolfram.com
• References: <j69104\$rda\$1@smc.vnet.net> <j6e5ti\$kbr\$1@smc.vnet.net> <j6h3kn\$74t\$1@smc.vnet.net>

```What about setting up a regular column "esoteric of the week" naming
functions that are rarely used ?

Clip[x]

which I (shame on me) didn't know until this evening. Did you?

Wolfgang

"Richard Fateman" <fateman at cs.berkeley.edu> schrieb im Newsbeitrag
news:j6h3kn\$74t\$1 at smc.vnet.net...
> On 10/3/2011 10:34 PM, Stefan Salanski wrote:
>
>>
>> All these solutions are very interesting, and they all work, but I
>> believe the simplest solution is actually a built in function,
>> specifically: IntegerExponent[].
>> IntegerExponent[n,b] returns the highest power of b which divides n,
>> which for b=10, is the number of trailing zeroes of n.
>>
> why yes, all you need is one esoteric function.
> Proof that it is esoteric?  All the previous posters (me too) were
> unaware of it. And presumably all the people who read the question
> and
> did not post anything ...
>
>
> The first example in the documentation illustrates exactly this
> usage.
>
> RJF
>
>

```

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