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Re: Taking the Arg of a complex number

  • To: mathgroup at smc.vnet.net
  • Subject: [mg122089] Re: Taking the Arg of a complex number
  • From: Simon <simonjtyler at gmail.com>
  • Date: Thu, 13 Oct 2011 03:47:43 -0400 (EDT)
  • Delivered-to: l-mathgroup@mail-archive0.wolfram.com
  • References: <j73grj$fvk$1@smc.vnet.net>
  • Reply-to: comp.soft-sys.math.mathematica at googlegroups.com

If you put phi in the principle range, then it works:

In[1]:= FullSimplify[Arg[A Exp[I phi]], A > 0 && -Pi < phi <= Pi]
Out[1]= phi

c.f.

In[2]:= FullSimplify[Arg[A Exp[I phi]], A > 0 && 0 < phi < 2 Pi]
Out[2]= Arg[E^(I phi)]



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