Re: Taking the Arg of a complex number
- To: mathgroup at smc.vnet.net
- Subject: [mg122089] Re: Taking the Arg of a complex number
- From: Simon <simonjtyler at gmail.com>
- Date: Thu, 13 Oct 2011 03:47:43 -0400 (EDT)
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- References: <j73grj$fvk$1@smc.vnet.net>
- Reply-to: comp.soft-sys.math.mathematica at googlegroups.com
If you put phi in the principle range, then it works: In[1]:= FullSimplify[Arg[A Exp[I phi]], A > 0 && -Pi < phi <= Pi] Out[1]= phi c.f. In[2]:= FullSimplify[Arg[A Exp[I phi]], A > 0 && 0 < phi < 2 Pi] Out[2]= Arg[E^(I phi)]