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Re: Taking the Arg of a complex number
- To: undisclosed-recipients:;
- Subject: [mg122106] Re: Taking the Arg of a complex number
- From: Alexei Boulbitch <Alexei.Boulbitch at iee.lu>
- Date: Fri, 14 Oct 2011 05:53:47 -0400 (EDT)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
Here ComplexExpand should help. Try this:
(* This is youe expression*)
x=Exp[I*\[CurlyPhi]]
E^(I \[CurlyPhi])
(* This is the answer *)
y=ComplexExpand[Arg@x]
ArcTan[Cos[\[CurlyPhi]],Sin[\[CurlyPhi]]]
(* Let us check, if it returns an expected result *)
y/.\[CurlyPhi]->\[Pi]/4
\[Pi]/4
Have fun.
Would appreciate any help here, endless Googling has not revealed the answer to me:
If I define a complex number symbolically, such as x = A Exp[I phi], why does Arg[x] never return the answer I expect, phi? Using Refine with the as sumptions phi is real and between 0 and 2 pi, and that A is greater than 0 doesn't seem to help. All I get is Arg[Exp[I phi]]
Alexei BOULBITCH, Dr., habil.
IEE S.A.
ZAE Weiergewan,
11, rue Edmond Reuter,
L-5326 Contern, LUXEMBOURG
Office phone : +352-2454-2566
Office fax: +352-2454-3566
mobile phone: +49 151 52 40 66 44
e-mail: alexei.boulbitch at iee.lu<mailto:alexei.boulbitch at iee.lu>
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