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Re: Table to calculate faster
*To*: mathgroup at smc.vnet.net
*Subject*: [mg122440] Re: Table to calculate faster
*From*: Oliver Ruebenkoenig <ruebenko at wolfram.com>
*Date*: Fri, 28 Oct 2011 05:37:33 -0400 (EDT)
*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com
*References*: <201110271032.GAA08914@smc.vnet.net>
Also, masonry is missing. Some ideas could be to use
T[..]:=T[..]=Evaluate[....]
or some such combination.
It is really better to send examples that actually have working code.
Another approach could be to use linear algebra A.T=b
Oliver
On Thu, 27 Oct 2011, Jacopo Bertolotti wrote:
> Maybe it's just me but it looks like the definition of each T[n,t]
> depends on the evaluation of the matrix itself on a previous time and so
> on iteratively. Since the code does not include any starting condition
> at t==0 all three definition enter a infinite loop preventing any useful
> evaluation.
>
> Best regards
>
> Jacopo
>
> On 10/26/2011 11:38 PM, Michelle Maul wrote:
>> I am trying to perform a heat transfer calculation on a wall with
>> transient heating. I am using rules so that we can easily change the
>> material. I want to be able to do several hundred time steps but I am
>> only able to get about 10 in an hour. It is a pretty straight forward
>> calculation so I'm wondering why it is taking so long to compute.
>> This is a calculation that Excel would be good at because it is taking
>> data from the cells above it to solve. Help please
>>
>> T[0, t_] := (1. -
>> 2. \[Tau] - (2. \[Tau] Subscript[h, in] \[CapitalDelta]x)/k) T[
>> 0, t - 1] +
>> 2. \[Tau] T[1,
>> t - 1] + (2. \[Tau] Subscript[h, in] \[CapitalDelta]x)/k*
>> Subscript[T, in] /. masonry;
>>
>> T[m_, t_] := \[Tau] (T[m - 1, t - 1] + T[m + 1, t - 1]) + (1. -
>> 2. \[Tau]) T[m, t - 1] /. masonry;
>>
>> T[5, t_] := (1. - 2. \[Tau] -
>> 2. \[Tau] (Subscript[h, out] \[CapitalDelta]x)/k) T[5,
>> t - 1] + 2. \[Tau] T[4, t - 1] +
>> 2. \[Tau] (Subscript[h, out] \[CapitalDelta]x)/
>> k*(Subscript[T, out] /. {x -> t}) +
>> 2. \[Tau] (\[Kappa] *(Subscript[q,
>> solar] /. {x -> t}) \[CapitalDelta]x)/k /. masonry;
>>
>> solution = Transpose[Table[T[n, x], {n, 0, 5}, {x, 0, 24}]]
>>
>> Thank you
>>
>>
>
>
>
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