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Re: two coupled differential equations


> x1'[t] == -k1*x1[t]
> x2'[t] == k2*x1[t]-k3*x2[t]/(k4+x2[t])

In this particular case the set can be reduced to a single differential equation: solve the first one (by hand!) and substitute the solution to the second one. You will get a single ODE for x2.

Even better, obtain k1 by fitting the experimental data for x1(t) to the analytical solution and use the second equation to fit k2 thru k4.

Themis




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