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Re: two coupled differential equations
- To: mathgroup at smc.vnet.net
- Subject: [mg121291] Re: two coupled differential equations
- From: Themis Matsoukas <tmatsoukas at me.com>
- Date: Wed, 7 Sep 2011 05:42:03 -0400 (EDT)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
> x1'[t] == -k1*x1[t]
> x2'[t] == k2*x1[t]-k3*x2[t]/(k4+x2[t])
In this particular case the set can be reduced to a single differential equation: solve the first one (by hand!) and substitute the solution to the second one. You will get a single ODE for x2.
Even better, obtain k1 by fitting the experimental data for x1(t) to the analytical solution and use the second equation to fit k2 thru k4.
Themis
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