Mathematica 9 is now available
Services & Resources / Wolfram Forums / MathGroup Archive
-----

MathGroup Archive 2011

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: boundary conditions

  • To: mathgroup at smc.vnet.net
  • Subject: [mg121551] Re: boundary conditions
  • From: Peter Pein <petsie at dordos.net>
  • Date: Mon, 19 Sep 2011 07:06:32 -0400 (EDT)
  • Delivered-to: l-mathgroup@mail-archive0.wolfram.com
  • References: <j54nme$91f$1@smc.vnet.net>

Am 18.09.2011 14:20, schrieb goli:
> what is the difference between these boundary conditions? do they
> represent the same thing?
> Derivative[0,1]v[t,0]==0
> v(0,1)[t,0]==0
> 

Hi,

you did not try to enter the two lines above, did you?

The first one would make sense if it would read

Derivative[0,1][v][t,0]==0

I guess you know about the meaning, because you're asking for BCs.

But I can't imagine how

v(0,1)[t,0]==0

should make sense without an extension of Mathematica's parser.


Peter




  • Prev by Date: Changing excel table with Wolfram Mathematica
  • Next by Date: Re: Replace & Rationalize
  • Previous by thread: Re: boundary conditions
  • Next by thread: Re: boundary conditions