MathGroup Archive 2012

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: troublesome integral

  • To: mathgroup at
  • Subject: [mg126033] Re: troublesome integral
  • From: danl at
  • Date: Fri, 13 Apr 2012 04:52:18 -0400 (EDT)
  • Delivered-to:
  • References: <jm64ib$6la$>

On Thursday, April 12, 2012 3:42:51 AM UTC-5, peter lindsay wrote:
> A couple of colleagues wondered about this. I've sent it on to support @ wolfram who are escalating it to the developers. Possibly someone here has an answer though ?
> Integrate[Cos[\[Beta]] Exp[I z Cos[\[Beta]-\[Alpha]]],{\[Beta],0,2 \[Pi]},Assumptions->z\[Element]Reals]
> doesn't seem to run.
> Answer should be
> 2 I \[Pi] BesselJ[1,z] Cos[\[Alpha]]  [ I think ]
> thanks
> Peter Lindsay

You can do this by translating so that the cosine in the exponential has a simple argument of 'b', recognizing that by periodicity you need not change the range of integration.

In[190]:= Integrate[Cos[b + a] Exp[I*z*Cos[b]], {b, 0, 2*Pi}, 
 Assumptions -> {Element[{a, z}, Reals]}]

Out[190]= 2*I*Pi*BesselJ[1, z]*Cos[a]

Daniel Lichtblau
Wolfram Research

  • Prev by Date: Re: What characters are allowed in mathematica variable names? i.e. how
  • Next by Date: Using "EventLocator" with NDSolve
  • Previous by thread: troublesome integral
  • Next by thread: Re: troublesome integral