Re: Transcendental functions
- To: mathgroup at smc.vnet.net
- Subject: [mg126300] Re: Transcendental functions
- From: Murray Eisenberg <murray at math.umass.edu>
- Date: Sun, 29 Apr 2012 02:12:12 -0400 (EDT)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- References: <201204280925.FAA00665@smc.vnet.net>
- Reply-to: murray at math.umass.edu
TrigToExp[ ArcTan[x] ] (I/2)*Log[1 - I*x] - (I/2)*Log[1 + I*x] Depending on when you want to replace ArcTan by its complex Log equivalent, you might handle an expression involving it so: func[ArcTan[x]] /. ArcTan[z_] :> TrigToExp[ArcTan[z]] On 4/28/12 5:25 AM, David Egan wrote: > Hi, > I am trying to teach mathematica to recognize this function > > ArcTan[x] - I/2 Log [(I + x)/(I - x)] == 0 > > Any thoughts on how to force mathematica to use it in simplifications. > Thanks > David > -- Murray Eisenberg murray at math.umass.edu Mathematics & Statistics Dept. Lederle Graduate Research Tower phone 413 549-1020 (H) University of Massachusetts 413 545-2859 (W) 710 North Pleasant Street fax 413 545-1801 Amherst, MA 01003-9305
- References:
- Transcendental functions
- From: David Egan <davee62@earthlink.net>
- Transcendental functions