Re: NDSolve curve - obtain single value from curve at t:=d

*To*: mathgroup at smc.vnet.net*Subject*: [mg127735] Re: NDSolve curve - obtain single value from curve at t:=d*From*: design <design at rcn.com>*Date*: Fri, 17 Aug 2012 03:46:24 -0400 (EDT)*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com*Delivered-to*: l-mathgroup@wolfram.com*Delivered-to*: mathgroup-newout@smc.vnet.net*Delivered-to*: mathgroup-newsend@smc.vnet.net*References*: <k0d1ta$m0c$1@smc.vnet.net> <k0fjee$q8q$1@smc.vnet.net>

Peter Thank you. I'm fascinated with the approach but still trying to integrate it into the app. Joe On Wednesday, August 15, 2012 3:34:38 AM UTC-4, Peter Pein wrote: > Am 14.08.2012 10:23, schrieb design: > > > Customized annuity applet; > > > I need to find the value of sol1 at t = d; > > > d, age, remaining life, fundrate, (and others) are all sliders; > > > Overall apples is working well > > > > > > d = age + remainingLife; > > > eqn1 = y'[t] == fundRate/100*y[t] - annuityAmt;=E2=80=A8sol1 = y[t]/. NDSolve[{eqn1, y[age] == startValue}, y[t], {t, age, 110}]; > > > > > > I have tried the sol1 iteration with {d,d,110} and many other approaches to no avail. > > > > > > Suggestions appreciated!! > > > > > Hi, > > > > DSolve[{y'[t] == fundRate/100*y[t] - annuityAmt, > > y[age] == startValue}, y[t], t] > > > > --> {{y[t] -> (1/fundRate) > > E^(-((age fundRate)/ > > 100)) (100 annuityAmt E^((age fundRate)/100) - > > 100 annuityAmt E^((fundRate t)/100) + > > E^((fundRate t)/100) fundRate startValue)}} > > > > doesn't help? > > > > In simple cases, try the exact solution. Even if the calculation needs a > > while (not for this differential equation), it's worth it. > > > > Peter On Wednesday, August 15, 2012 3:34:38 AM UTC-4, Peter Pein wrote: > Am 14.08.2012 10:23, schrieb design: > > > Customized annuity applet; > > > I need to find the value of sol1 at t = d; > > > d, age, remaining life, fundrate, (and others) are all sliders; > > > Overall apples is working well > > > > > > d = age + remainingLife; > > > eqn1 = y'[t] == fundRate/100*y[t] - annuityAmt;=E2=80=A8sol1 = y[t]/. NDSolve[{eqn1, y[age] == startValue}, y[t], {t, age, 110}]; > > > > > > I have tried the sol1 iteration with {d,d,110} and many other approaches to no avail. > > > > > > Suggestions appreciated!! > > > > > Hi, > > > > DSolve[{y'[t] == fundRate/100*y[t] - annuityAmt, > > y[age] == startValue}, y[t], t] > > > > --> {{y[t] -> (1/fundRate) > > E^(-((age fundRate)/ > > 100)) (100 annuityAmt E^((age fundRate)/100) - > > 100 annuityAmt E^((fundRate t)/100) + > > E^((fundRate t)/100) fundRate startValue)}} > > > > doesn't help? > > > > In simple cases, try the exact solution. Even if the calculation needs a > > while (not for this differential equation), it's worth it. > > > > Peter On Wednesday, August 15, 2012 3:34:38 AM UTC-4, Peter Pein wrote: > Am 14.08.2012 10:23, schrieb design: > > > Customized annuity applet; > > > I need to find the value of sol1 at t = d; > > > d, age, remaining life, fundrate, (and others) are all sliders; > > > Overall apples is working well > > > > > > d = age + remainingLife; > > > eqn1 = y'[t] == fundRate/100*y[t] - annuityAmt;=E2=80=A8sol1 = y[t]/. NDSolve[{eqn1, y[age] == startValue}, y[t], {t, age, 110}]; > > > > > > I have tried the sol1 iteration with {d,d,110} and many other approaches to no avail. > > > > > > Suggestions appreciated!! > > > > > Hi, > > > > DSolve[{y'[t] == fundRate/100*y[t] - annuityAmt, > > y[age] == startValue}, y[t], t] > > > > --> {{y[t] -> (1/fundRate) > > E^(-((age fundRate)/ > > 100)) (100 annuityAmt E^((age fundRate)/100) - > > 100 annuityAmt E^((fundRate t)/100) + > > E^((fundRate t)/100) fundRate startValue)}} > > > > doesn't help? > > > > In simple cases, try the exact solution. Even if the calculation needs a > > while (not for this differential equation), it's worth it. > > > > Peter