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Re: Group and Replace itens sequence in a list

  • To: mathgroup at smc.vnet.net
  • Subject: [mg127818] Re: Group and Replace itens sequence in a list
  • From: Ulrich Arndt <ulrich.arndt at data2knowledge.de>
  • Date: Thu, 23 Aug 2012 20:52:55 -0400 (EDT)
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  • References: <20120823065202.F18956843@smc.vnet.net>

This one requires no X

ls = ReplaceRepeated[l, {x___, a, b, a, y___} -> {{x}, {y}}]
Extract[ls, Position[ls, {a___?AtomQ}]]

Ulrich

Am 23.08.2012 um 08:52 schrieb Murta:

> Hi All
>
>   I have a simple problem that is:
>
> l={1,2,3,a,b,a,4,5,6,a,b,c,7,8,9,a,b,a,10,11,12}
>
> I want to replace all a,b,a sequence by X to get:
>
> l={1,2,3,X,4,5,6,a,b,7,8,9,X,10,11,12}
>
> Then I want to group it by X intervals as
> l={{1,2,3},{4,5,6,a,b,7,8,9},{10,11,12}}
>
> If I don't need to put the intermediate X, even better!
> I think the with pattern, RaplaceAll and DeleteCases I can do It. Some clue?
> Tks
> Murta
>
>
>




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