Re: Equation solving problem
- To: mathgroup at smc.vnet.net
- Subject: [mg125075] Re: Equation solving problem
- From: Szabolcs Horvát <szhorvat at gmail.com>
- Date: Mon, 20 Feb 2012 02:52:18 -0500 (EST)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- References: <jhqmm3$fae$1@smc.vnet.net>
On 2/19/2012 1:33 PM, Juhász Péter wrote: > I have the following problem: I would like to solve a set of 3 > equations, but Mathematica's solution involves unknown variables. My > input was: > > Solve[{nc^2/Sqrt[1 - v^2/c^2] == mc^2/Sqrt[1 - b^2/c^2] + pc, > nv/Sqrt[1 - v^2/c^2] == (mb Cos[\[Alpha]])/Sqrt[1 - b^2/c^2] + > p Sin[\[Alpha]], (mb Sin[\[Alpha]])/Sqrt[1 - b^2/c^2] == > p Cos[\[Alpha]]}, {v, b, p}] > > And the output started like: > > {{v -> -(I c \[Sqrt](mc^4 nv^2 Cos[\[Alpha]]^2 - > 2 mb mc^2 nc^2 nv Cos[\[Alpha]]^3 + > mb^2 nc^4 Cos[\[Alpha]]^4 - mb^2 pc^2 Cos[\[Alpha]]^4 - > 2 mb mc^2 nc^2 nv Cos[\[Alpha]] Sin[\[Alpha]]^2 + > 2 mb^2 nc^4 Cos[\[Alpha]]^2 Sin[\[Alpha]]^2 - > 2 mb^2 pc^2 Cos[\[Alpha]]^2 Sin[\[Alpha]]^2 + > mb^2 nc^4 Sin[\[Alpha]]^4 - > mb^2 pc^2 Sin[\[Alpha]]^4))/(mb pc Sqrt[ > Cos[\[Alpha]]^4 + 2 Cos[\[Alpha]]^2 Sin[\[Alpha]]^2 + > Sin[\[Alpha]]^4]), > b -> -1/(nv pc) (\[Sqrt](-c^2 mc^4 nv^2 + c^2 nv^2 pc^2 + > 2 c^2 mb mc^2 nc^2 nv Cos[\[Alpha]] - > c^2 mb^2 nc^4 Cos[\[Alpha]]^2 - > 2 c^2 mb^2 nc^4 Sin[\[Alpha]]^2 + > 2 c^2 mb mc^2 nc^2 nv Sin[\[Alpha]] Tan[\[Alpha]] - > c^2 mb^2 nc^4 Sin[\[Alpha]]^2 Tan[\[Alpha]]^2)), > .... .... .... > > And so on. It is clear, that if we look at the solution for v, it > involves unknowns b and p. If anyone could tell me what I did wrong, I > would highly appreciate it. > Mathematica treats nc as a single variable with a two latter name. If you mean the product of n and c, you need to write n c (note that space between them) or n*c. The solution it gives you does not include "v", but only "nv" (and other similar variables). -- Szabolcs Horvát Visit Mathematica.SE: http://mathematica.stackexchange.com/