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Re: simplifying algebraic expressions with Null

  • To: mathgroup at smc.vnet.net
  • Subject: [mg125133] Re: simplifying algebraic expressions with Null
  • From: Alexei Boulbitch <Alexei.Boulbitch at iee.lu>
  • Date: Thu, 23 Feb 2012 05:47:47 -0500 (EST)
  • Delivered-to: l-mathgroup@mail-archive0.wolfram.com

Hi,

how to simplify an algebraic expression such that if a Null expression
is present then the whole algebraic expression gets simplified to
Null?
I'm using Null to represent missing data values. So after some
calculations on data with missing values (Null) I get expressions
involving Null. I'd like to simplify it to Null.
Example:

x=List[List[1,2],List[Plus[2,Null],3],List[4,5]];
Simplify x such that Plus[2,Null] gets replaced with Null, yielding,
lets say, y:
y=x // SpecialSimplification
List[List[1,2],List[Null,3],List[4,5]]

Obviously I'd want this to work on arrays, matrices, etc.. i.e.
applying the simplification up to the algebraic expression and not
further. I mean, I'd not want this to happen:
x=List[List[1,2],List[Plus[2,Null],3],List[4,5]];
y=x // SpecialSimplification
List[List[1,2],Null,List[4,5]]

or

x=List[List[1,2],List[Plus[2,Null],3],List[4,5]];
y=x // SpecialSimplification
Null

In other words, I'd like to be able to set the Null expression as the
absorbing element for any algebraic expression.

Thanks.

Hi, Ramiro,

What about this:

x=List[List[1,2],List[Subtract[2,Null],3],List[4,5]]
{{1,2},{2-Null,3},{4,5}}

x/.{a_+Null,b_}->Null/.{a_-Null,b_}->Null
{{1,2},Null,{4,5}}

Have fun, Alexei

Alexei BOULBITCH, Dr., habil.
IEE S.A.
ZAE Weiergewan,
11, rue Edmond Reuter,
L-5326 Contern, LUXEMBOURG

Office phone :  +352-2454-2566
Office fax:       +352-2454-3566
mobile phone:  +49 151 52 40 66 44

e-mail: alexei.boulbitch at iee.lu<mailto:alexei.boulbitch at iee.lu>




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