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Re: Extension to BinLists Function

  • To: mathgroup at smc.vnet.net
  • Subject: [mg124088] Re: Extension to BinLists Function
  • From: Bob Hanlon <hanlonr357 at gmail.com>
  • Date: Sun, 8 Jan 2012 04:27:17 -0500 (EST)
  • Delivered-to: l-mathgroup@mail-archive0.wolfram.com
  • References: <201201071019.FAA19388@smc.vnet.net>

With my version I do not have a problem with using infinities as the boundaries

$Version

"8.0 for Mac OS X x86 (64-bit) (October 5, 2011)"

breakPoints = {-Infinity, 2, 5, 7, Infinity};

data1 = {{1, 0.936229}, {3, 0.128096}, {2, 0.393583}, {1, 0.301525},
   {4, 0.503822}, {5, 0.253597}, {6, 0.0835316}, {2, 0.0068356}};

res1 = First /@ BinLists[data1, {breakPoints}, {{-Infinity, Infinity}}]

{{{1, 0.936229}, {1, 0.301525}}, {{3, 0.128096}, {2, 0.393583}, {4,
   0.503822}, {2, 0.0068356}}, {{5, 0.253597}, {6, 0.0835316}}, {}}

For your second example, note that your bins do not cover all of your
data and those items with second element below 0.1 or greater than 1
should not appear.

brkPts = Range[.1, 1.0, .1];

res2 = BinLists[data1, {{-Infinity, Infinity}}, {brkPts}] // First

{{{3, 0.128096}}, {{5, 0.253597}}, {{2, 0.393583}, {1, 0.301525}}, {}, {{4,
   0.503822}}, {}, {}, {}, {{1, 0.936229}}}

To obtain the result that you stated, I redefine your brkPts

brkPts2 = Flatten[{-Infinity, Range[.1, 1.0, .1], Infinity}];

res3 = BinLists[data1, {{-Infinity, Infinity}}, {brkPts2}] // First

{{{6, 0.0835316}, {2, 0.0068356}}, {{3, 0.128096}}, {{5, 0.253597}}, {{2,
   0.393583}, {1, 0.301525}}, {}, {{4, 0.503822}}, {}, {}, {}, {{1,
   0.936229}}, {}}

For your third example, brkPts2 is undefined. I will use brkPts2 from
my last example. For the general case, I would use Cases and Table

data2 = {{1, 0.936229, {2, .03}}, {3, 0.128096, {9, .73}}, {2,
    0.393583, {4, .22}},
   {8, 0.301525, {2, .18}}, {1, 0.503822, {6, .19}}, {5, 0.253597, {3, .20}},
   {6, 0.0835316, {3, .29}}, {2, 0.0068356, {4, .81}}};

binLists[array_List, breakPts_List, pos_List: {}] :=
 If[pos == {},
  BinLists[array, {breakPts}],
  Table[Cases[
    array, _?(breakPts[[k]] <= #[[Sequence @@ pos]] < breakPts[[k + 1]] &],
   {k, Length[breakPts] - 1}]]

res1 == binLists[data1, breakPoints, {1}]

True

res2 == binLists[data1, brkPts, {2}]

True

res3 == binLists[data1, brkPts2, {2}]

True

binLists[data2, brkPts2, {3, 2}]

{{{1, 0.936229, {2, 0.03}}}, {{8, 0.301525, {2, 0.18}}, {1,
   0.503822, {6, 0.19}}}, {{2, 0.393583, {4, 0.22}}, {5,
   0.253597, {3, 0.2}}, {6, 0.0835316, {3, 0.29}}}, {}, {}, {}, {}, {{3,
   0.128096, {9, 0.73}}}, {{2, 0.0068356, {4, 0.81}}}, {}, {}}


Bob Hanlon


On Sat, Jan 7, 2012 at 5:19 AM, Don <donabc at comcast.net> wrote:
> Thank you Bob for your response to my problem.
>
> I was unable to get a correct answer in exactly the way
> you have formulated it.
>
> When I do
>
>
> breakPoints = {-Infinity, 2, 5, 7, Infinity};
>
> data1 = {{1, 0.936229}, {3, 0.128096}, {2, 0.393583}, {1, 0.301525},
> {4, 0.503822}, {5, 0.253597}, {6, 0.0835316}, {2, 0.0068356}};
>
> BinLists[data1, {breakPoints}, {{-Infinity, Infinity}}]
>
> I get an error message which says:
>
> Interpolation::indat: "Data point {-\[Infinity], 0} contains abscissa -\[Infinity], which is not a real number.
>
> And it suggests I click on a link whch redirects me to:
>  ref/message/Interpolation/indat for further
> explanation.
>
> I got around the Infinity problem in
> the error message  by replacing the Infinity in both the breakPoints vector
> and in {-Infinity, Infinity} with a number that is larger than any number
> in data1 but which is still finite:
>
> brkPts = {-100, 2, 5, 7, 100}
>
> and then tried BinLists again:
>
>
> BinLists[data1,{brkPts},{{-100,100}}]
>
> which did work and produced:
>
> {{{{1,0.936229},{1,0.301525}}},{{{3,0.128096},{2,0.393583},{4,0.503822},{2,0.0068356}}},{{{5,0.253597},{6,0.0835316}}},{{}}}
>
> But, I wanted to extend BinLists to being able to
> bin on any position in the data, not just the first element
> of a sublist.
>
> For example, if I wanted to bin on the second element
> in a sublist in data1, I don't see how to go about doing that
> with the above technique.
>
>
> Using the binLists function in my first post it would look like
> the following:
>
> brkPts = Range[.1, 1.0, .1]
> binLists[data1,brkPts, {2}]
>
> which results in the following:
>
> {{{6,0.0835316},{2,0.0068356}},{{3,0.128096}},{{5,0.253597}},{{2,0.393583},{1,0.301525}},{},{{4,0.503822}},{},{},{},{{1,0.936229}},{}}
>
>
> The third parameter, {2},  to binLists allows me to specify
> the element in a sublist of data1 which is to be used for binning,
> no matter how complicated a sublist  is (assuming, of course,
> that each sublist has the same structure).
>
> For example,  if I wanted to bin
> on the second element of the third element
> in each sublist of data2 below, the
> third input to binLists would be {3,2}:
>
>
> data2={{1,0.936229, {2,.03}},{3,0.128096, {9,.73}},{2,0.393583, {4,.22}},{8,0.301525, {2,.18}},{1,0.503822, {6,.19}},{5,0.253597, {3,.20}},{6,0.0835316, {3,.29}},{2,0.0068356, {4,.81}}};
>
> binLists[data2, brkPts2, {3,2}]
>
> which results in
>
> {{{1,0.936229,{2,0.03}}},{{8,0.301525,{2,0.18}},{1,0.503822,{6,0.19}}},{{2,0.393583,{4,0.22}},{5,0.253597,{3,0.2}},{6,0.0835316,{3,0.29}}},{},{},{},{},{{3,0.128096,{9,0.73}}},{{2,0.0068356,{4,0.81}}},{},{}}
>
>
> I don't see any way from the documentation to
> get BinLists to do this as it does not take as input
> the specification of the element position in the data
> upon which binning is to occur, like {3,2} above.
>
> The trouble with binLists, as  mentioned in the first post, is that
> it is rather clumsy and depends on nested For loops
> to do most of the work
> which, I assume from past experience, is quite slow
> in terms of processor time.   I was
> wondering if there is a faster, perhaps more elegant
> way, to accomplis this.
>
> Thank you.
>
> Don
>



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