Re: Engineering requests
- To: mathgroup at smc.vnet.net
- Subject: [mg125417] Re: Engineering requests
- From: Dana DeLouis <dana01 at me.com>
- Date: Tue, 13 Mar 2012 03:04:26 -0500 (EST)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
On Mar 12, 5:07 am, "McHale, Paul" <Paul.McH... at excelitas.com> wrote: > The interval function looks a little to foreign to this intended purpose. Slight changes in the representation you chose seems to break it quickly. <snip> > > (* using table (correct answers) *) > > R1=R1int; > > R2=R2int; > > Table[5/(Ra+Rb) Rb,{Ra,R1},{Rb,R2}]// Max > > Table[5/(Ra+Rb) Rb,{Ra,R1},{Rb,R2}]// Min > > > Out[3]= 1.34146 > > Out[4]= 0.985401 vs: 5./(1+r1/r2) Interval[{0.985401,1.34146}] Hi. Not sure what was changed, but I believe one needs to eliminate duplicate variables. I think you need to reduce the equation so that each interval occurs once. Another way might be... The numbers used are the min and max of the intervals involved. 5. * 27000 / (27000+110000) 0.985401 5.* 33000 / (90000+33000) 1.34146 = = = = = = = = = = HTH :>) Dana DeLouis = = = = = = = = = =
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- Re: Engineering requests