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Re: Different answers in mathematica and my calculator.
-1 is a real cube root of -1, so it's not quite correct to say "(-1)^(1/3) is complex". Two cube roots of -1 ARE complex, of course. Bobby On Tue, 20 Mar 2012 02:21:56 -0500, psycho_dad <s.nesseris at gmail.com> wrote: > I'm afraid that Sec corresponds to 1/Cos in the sense of 2 and 1/2 > respectively. The function you want is ArcCos (inverse cosine). > > As for the first question, mathematica is right, so you are either doing > something wrong on the calculator or it doesn't support complex numbers, > as Power[2(-2)+3, (3)^-1]=(-1)^(1/3) is complex. > -- DrMajorBob at yahoo.com