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Re: Problem with SetDelayed lhs:=rhs
- To: mathgroup at smc.vnet.net
- Subject: [mg128679] Re: Problem with SetDelayed lhs:=rhs
- From: "Chris Degnen" <degnen at cwgsy.net>
- Date: Fri, 16 Nov 2012 01:52:16 -0500 (EST)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- Delivered-to: l-mathgroup@wolfram.com
- Delivered-to: mathgroup-newout@smc.vnet.net
- Delivered-to: mathgroup-newsend@smc.vnet.net
- References: <k466r8$a8g$1@smc.vnet.net>
You could just draw in the value of k outside the pattern match:
k = 5;
f[j_] := rhs[k, j];
f[4]
zahava asked:
>
> An assignment using SetDelayed, lhs := rhs, maintains rhs in completely
> unevaluated form.
> Thus, if k=5, say, the assignment
>
> In[1] = f[k,j_]:=rhs[k,j]
>
> yields
>
> In[2] = ?f
> Global`f
> f[5,j_]:=rhs[k,j]
>
> How can I force the k on the right hand side to be evaluated so that ?f
> will yield
> f[5,j_]:=rhs[5,j] ?
>
> Of course, I could define f[5,j_] manually, but I want to automate the
> procedure over a range of values of k.
>
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