Re: Problem with SetDelayed lhs:=rhs

*To*: mathgroup at smc.vnet.net*Subject*: [mg128679] Re: Problem with SetDelayed lhs:=rhs*From*: "Chris Degnen" <degnen at cwgsy.net>*Date*: Fri, 16 Nov 2012 01:52:16 -0500 (EST)*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com*Delivered-to*: l-mathgroup@wolfram.com*Delivered-to*: mathgroup-newout@smc.vnet.net*Delivered-to*: mathgroup-newsend@smc.vnet.net*References*: <k466r8$a8g$1@smc.vnet.net>

You could just draw in the value of k outside the pattern match: k = 5; f[j_] := rhs[k, j]; f[4] zahava asked: > > An assignment using SetDelayed, lhs := rhs, maintains rhs in completely > unevaluated form. > Thus, if k=5, say, the assignment > > In[1] = f[k,j_]:=rhs[k,j] > > yields > > In[2] = ?f > Global`f > f[5,j_]:=rhs[k,j] > > How can I force the k on the right hand side to be evaluated so that ?f > will yield > f[5,j_]:=rhs[5,j] ? > > Of course, I could define f[5,j_] manually, but I want to automate the > procedure over a range of values of k. >