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Re: Problem with SetDelayed lhs:=rhs

  • To: mathgroup at smc.vnet.net
  • Subject: [mg128679] Re: Problem with SetDelayed lhs:=rhs
  • From: "Chris Degnen" <degnen at cwgsy.net>
  • Date: Fri, 16 Nov 2012 01:52:16 -0500 (EST)
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  • References: <k466r8$a8g$1@smc.vnet.net>

You could just draw in the value of k outside the pattern match:

k = 5;
f[j_] := rhs[k, j];
f[4]


zahava asked:
>
> An assignment using SetDelayed, lhs := rhs, maintains rhs in completely 
> unevaluated form.
> Thus, if k=5, say, the assignment
>
> In[1] = f[k,j_]:=rhs[k,j]
>
> yields
>
> In[2] = ?f
> Global`f
> f[5,j_]:=rhs[k,j]
>
> How can I force the k on the right hand side to be evaluated so that ?f 
> will yield
> f[5,j_]:=rhs[5,j] ?
>
> Of course, I could define f[5,j_] manually, but I want to automate the 
> procedure over a range of values of k.
> 





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