simultaneous equation
- To: mathgroup at smc.vnet.net
- Subject: [mg128741] simultaneous equation
- From: "Trichy V. Krishnan" <biztvk at nus.edu.sg>
- Date: Thu, 22 Nov 2012 04:33:50 -0500 (EST)
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Hi:
When I solve a simultaneous equation, the output looks as follows. How do I remove those ?1.? and the annoying wiggles in the superscript position in so many places.
With regards
trichy
Here is the whole thing. It's a small program... When I ran it anew, the superscript-wiggles are gone but the "1." persists. Thanks for the help.
trichy
In[1]:
x1 = 0.5 + (1/(4 t1)) (rsm - rsk);
x2 = 0.5 + (1/(4 t2)) (rLm - rLk);
x3 = 0.5 + (1/4) (rLk - n rsk);
x4 = 0.5 + (1/4) (rLm - n rsm);
ssk = a b x1 + (1 - a) g x3;
sLk = a (1 - b) x2 + (1 - a) g (1 - x3);
ssm = a b (1 - x1) + (1 - a) (1 - g) x4;
sLm = a (1 - b) (1 - x2) + (1 - a) (1 - g) (1 - x4);
Pik = ssk rsk + sLk rLk;
Pim = ssm rsm + sLm rLm;
Pidsm = D[Pim, rsm]; PidLm = D[Pim, rLm];
Solve[Pidsm == 0 && PidLm == 0, {rsm, rLm}]
Out[1]:
{{rsm -> -((0.5 a b + 0.5 (1. - 1. a) (1. - 1. g) + (0.25 a b rsk)/
t1) (-0.5 (1. - 1. a) (1. - 1. g) - (0.5 a (1. - 1. b))/
t2) - 1. (0.25 (1. - 1. a) (1. - 1. g) +
0.25 (1. - 1. a) (1. - 1. g) n) (0.5 a (1. - 1. b) +
0.5 (1. - 1. a) (1. - 1. g) + (0.25 a (1. - 1. b) rLk)/
t2))/(-1. (0.25 (1. - 1. a) (1. - 1. g) +
0.25 (1. - 1. a) (1. - 1. g) n)^2 + (-0.5 (1. - 1. a) (1. -
1. g) n - (0.5 a b)/t1) (-0.5 (1. - 1. a) (1. - 1. g) - (
0.5 a (1. - 1. b))/t2)),
rLm -> (1. (0.25 (1. - 1. a) (1. - 1. g) +
0.25 (1. - 1. a) (1. - 1. g) n) ((0.5 a b +
0.5 (1. - 1. a) (1. - 1. g) + (0.25 a b rsk)/
t1) (-0.5 (1. - 1. a) (1. - 1. g) - (0.5 a (1. - 1. b))/
t2) - 1. (0.25 (1. - 1. a) (1. - 1. g) +
0.25 (1. - 1. a) (1. - 1. g) n) (0.5 a (1. - 1. b) +
0.5 (1. - 1. a) (1. - 1. g) + (0.25 a (1. - 1. b) rLk)/
t2)))/((-1. (0.25 (1. - 1. a) (1. - 1. g) +
0.25 (1. - 1. a) (1. - 1. g) n)^2 + (-0.5 (1. -
1. a) (1. - 1. g) n - (0.5 a b)/
t1) (-0.5 (1. - 1. a) (1. - 1. g) - (0.5 a (1. - 1. b))/
t2)) (-0.5 (1. - 1. a) (1. - 1. g) - (0.5 a (1. - 1. b))/
t2)) - (0.5 a (1. - 1. b) + 0.5 (1. - 1. a) (1. - 1. g) + (
0.25 a (1. - 1. b) rLk)/t2)/(-0.5 (1. - 1. a) (1. - 1. g) - (
0.5 a (1. - 1. b))/t2)}}