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Re: Numerical expression
- To: mathgroup at smc.vnet.net
- Subject: [mg128816] Re: Numerical expression
- From: Dana DeLouis <dana01 at me.com>
- Date: Wed, 28 Nov 2012 03:16:54 -0500 (EST)
- Delivered-to: l-mathgroup@mail-archive0.wolfram.com
- Delivered-to: l-mathgroup@wolfram.com
- Delivered-to: mathgroup-newout@smc.vnet.net
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> ( ( 9(3)^1/2+4(23)^1/2)^1/3 + (9(3)^1/2+4(23)^1/2)^1/3 ) / (3)^1/2)
Hi. Just to add to the others, if we "Assume" the following
k = (9*Sqrt[3] + 4*Sqrt[23])^ (1 / 3) ;
// Or...
k=k//FullSimplify
Sqrt[1/2 (13+Sqrt[69])]
Then what you have is:
(k+k) / Sqrt[3.]
3.76887
// Which matches what others have mentioned:
For this to equal 1, then k would have to equal
Sqrt[3] / 2
Perhaps your equation for the k part is off a little. ??
= = = = = = = = = =
HTH :>)
Dana DeLouis
Mac & Mathematica 8
= = = = = = = = = =
On Sunday, November 25, 2012 11:29:24 PM UTC-5, Massimo wrote:
> How could I handle in Mathematica this expression?
>
>
>
> ( ( 9(3)^1/2+4(23)^1/2)^1/3 + (9(3)^1/2+4(23)^1/2)^1/3 ) / (3)^1/2)
>
>
>
> With a lot of trouble I have found out that is equal 1,
>
> but how to get it with Mathematica?
>
>
>
> Thanks very much.
>
>
>
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>
>
>
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