Re: Numerical expression

*To*: mathgroup at smc.vnet.net*Subject*: [mg128816] Re: Numerical expression*From*: Dana DeLouis <dana01 at me.com>*Date*: Wed, 28 Nov 2012 03:16:54 -0500 (EST)*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com*Delivered-to*: l-mathgroup@wolfram.com*Delivered-to*: mathgroup-newout@smc.vnet.net*Delivered-to*: mathgroup-newsend@smc.vnet.net

> ( ( 9(3)^1/2+4(23)^1/2)^1/3 + (9(3)^1/2+4(23)^1/2)^1/3 ) / (3)^1/2) Hi. Just to add to the others, if we "Assume" the following k = (9*Sqrt[3] + 4*Sqrt[23])^ (1 / 3) ; // Or... k=k//FullSimplify Sqrt[1/2 (13+Sqrt[69])] Then what you have is: (k+k) / Sqrt[3.] 3.76887 // Which matches what others have mentioned: For this to equal 1, then k would have to equal Sqrt[3] / 2 Perhaps your equation for the k part is off a little. ?? = = = = = = = = = = HTH :>) Dana DeLouis Mac & Mathematica 8 = = = = = = = = = = On Sunday, November 25, 2012 11:29:24 PM UTC-5, Massimo wrote: > How could I handle in Mathematica this expression? > > > > ( ( 9(3)^1/2+4(23)^1/2)^1/3 + (9(3)^1/2+4(23)^1/2)^1/3 ) / (3)^1/2) > > > > With a lot of trouble I have found out that is equal 1, > > but how to get it with Mathematica? > > > > Thanks very much. > > > > > > > > __________ Informazioni da ESET Smart Security, versione del database = delle firme digitali 7729 (20121125) __________ > > > > Il messaggio =EF=BF=BD stato controllato da ESET Smart Security. > > > > www.nod32.it

**Follow-Ups**:**Re: Numerical expression***From:*Bob Hanlon <hanlonr357@gmail.com>

**Re: Numerical expression***From:*"Brambilla Roberto Luigi (RSE)" <Roberto.Brambilla@rse-web.it>