Re: Numerical expression

*To*: mathgroup at smc.vnet.net*Subject*: [mg128807] Re: Numerical expression*From*: Alexei Boulbitch <Alexei.Boulbitch at iee.lu>*Date*: Tue, 27 Nov 2012 03:51:36 -0500 (EST)*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com*Delivered-to*: l-mathgroup@wolfram.com*Delivered-to*: mathgroup-newout@smc.vnet.net*Delivered-to*: mathgroup-newsend@smc.vnet.net

How could I handle in Mathematica this expression? ( ( 9(3)^1/2+4(23)^1/2)^1/3 + (9(3)^1/2+4(23)^1/2)^1/3 ) / (3)^1/2) With a lot of trouble I have found out that is equal 1, but how to get it with Mathematica? Thanks very much. Hi, Massimo, The expression that you have written here does not look to have sense. Just evaluate this in Mathematica: ((Defer@(((9 ((3)^1)?2+4 ((23)^1)?2)^1)?3+((9 ((3)^1)?2+4 ((23)^1)?2)^1)?3))?((3)^1))?2 Is it what you had in mind? If yes, you can evaluate it straightforwardly: ((9 (3)^1/2 + 4 (23)^1/2)^1/3 + (9 (3)^1/2 + 4 (23)^1/2)^1/3)/(3)^1/ 2 // FullSimplify That's what you get out: 119/18 It seems that you may have had in mind this (evaluate it): Defer@((9 (3)^(1/2) + 4 (23)^(1/2))^(1/3) + (9 (3)^(1/2) + 4 (23)^(1/2))^(1/3))/(3)^(1/2) If yes, it also can be directly evaluated: ((9 (3)^(1/2) + 4 (23)^(1/2))^(1/3) + (9 (3)^(1/2) + 4 (23)^(1/2))^(1/ 3))/(3)^(1/2) // FullSimplify yielding 1 + Sqrt[23/3] but not 1. Probably you have had something else in mind. Have fun, Alexei Alexei BOULBITCH, Dr., habil. IEE S.A. ZAE Weiergewan, 11, rue Edmond Reuter, L-5326 Contern, LUXEMBOURG Office phone : +352-2454-2566 Office fax: +352-2454-3566 mobile phone: +49 151 52 40 66 44 e-mail: alexei.boulbitch at iee.lu