Re: Sum elements in a list with conditions
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- Subject: [mg128441] Re: Sum elements in a list with conditions
- From: Adriano Pascoletti <adriano.pascoletti at uniud.it>
- Date: Fri, 19 Oct 2012 02:44:44 -0400 (EDT)
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A solution with Sow and Reap
In[1]:= L = {{1, a}, {2, b}, {1, c}, {2, d}, {2, e}, {3, f}};
Reap[(Sow @@ Reverse[#1] & ) /@ L, _, {#1, Total[#2]} & ][[2]]
Out[1]= {{1, a + c}, {2, b + d + e}, {3, f}}
Adriano Pascoletti
2012/10/18 Guillermo Sanchez <guillermo.sanchez at hotmail.com>
> I have a list of sublist of pairs. I wish sum the second elements of
> the sublists when the first elements are equals
> Example:
> Int[]:={{1, a}, {2, b}, {1, c}, {2, d}, {2, e}, {3, f}}
> I hope
> Out[]:= {{1, a + c}, {2, b + c + e}, {3, f}}
>
> I can do it as is it is shown below but could any body find and
> easier solution.
>
>
> list1 = {{1, a}, {2, b}, {1, c}, {2, d}, {2, e}, {3, f}};
> list2 = GatherBy[list1, First];
> {l1, l2} = Transpose[Plus @@@ GatherBy[list, First]];
> Transpose[{l1/Length /@ list2 , l2}]
>
>
- References:
- Sum elements in a list with conditions
- From: Guillermo Sanchez <guillermo.sanchez@hotmail.com>
- Sum elements in a list with conditions