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Re: Sum elements in a list with conditions

  • To: mathgroup at smc.vnet.net
  • Subject: [mg128441] Re: Sum elements in a list with conditions
  • From: Adriano Pascoletti <adriano.pascoletti at uniud.it>
  • Date: Fri, 19 Oct 2012 02:44:44 -0400 (EDT)
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  • References: <20121018063647.0023568A4@smc.vnet.net>

A solution with Sow and Reap

In[1]:= L = {{1, a}, {2, b}, {1, c}, {2, d}, {2, e}, {3, f}};
  Reap[(Sow @@ Reverse[#1] & ) /@ L, _, {#1, Total[#2]} & ][[2]]
Out[1]= {{1, a + c}, {2, b + d + e}, {3, f}}

Adriano Pascoletti

2012/10/18 Guillermo Sanchez <guillermo.sanchez at hotmail.com>

> I have a list of sublist of pairs. I wish sum the second elements of
> the sublists when the first elements are equals
> Example:
> Int[]:={{1, a}, {2, b}, {1, c}, {2, d}, {2, e}, {3, f}}
> I hope
> Out[]:= {{1, a + c}, {2, b + c + e}, {3, f}}
>
> I can do it as  is it is shown below but could any body find and
> easier solution.
>
>
> list1 = {{1, a}, {2, b}, {1, c}, {2, d}, {2, e}, {3, f}};
> list2 = GatherBy[list1, First];
> {l1, l2} = Transpose[Plus @@@ GatherBy[list, First]];
> Transpose[{l1/Length /@ list2 , l2}]
>
>




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