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Re: Fourier Transform of a "step" function

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  • Subject: [mg128506] Re: Fourier Transform of a "step" function
  • From: PAR123 <reiser.paul at gmail.com>
  • Date: Thu, 25 Oct 2012 23:33:47 -0400 (EDT)
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UnitBox[(x/x0 - 1/2)] will give you a function that is unity from zero to x0. Multiply that by a+b x+c x^2 and take the Fourier transform:

FourierTransform[(a + b x + c x^2) UnitBox[(x/x0 - 1/2)], x, t]



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