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Re: Turning a Sequence into a List?
*To*: mathgroup at smc.vnet.net
*Subject*: [mg130516] Re: Turning a Sequence into a List?
*From*: Alexei Boulbitch <Alexei.Boulbitch at iee.lu>
*Date*: Thu, 18 Apr 2013 05:33:15 -0400 (EDT)
*Delivered-to*: l-mathgroup@mail-archive0.wolfram.com
*Delivered-to*: l-mathgroup@wolfram.com
*Delivered-to*: mathgroup-newout@smc.vnet.net
*Delivered-to*: mathgroup-newsend@smc.vnet.net
Hello, I'm playing with a problem with minimum coins to make change.
Here's a problem spot where I look at ways to make up 52 and 53 cents
(later I'll use v = Range[1,99].
v=Range[52,53];
sol=(Reduce[25q+10d+5n+p==# &&0<=p<5 &&0<=n<2 &&0<=d<3
&&0<=q<4,{q,d,n,p},Integers])& /@v
(* which gives {(q == 1 && d == 2 && n == 1 && p == 2) || (=
q == 2 && d
== 0 &&
n == 0 && p == 2), (q == 1 && d == 2 && n == 1 &&
p == 3) || (q == 2 && d == 0 && n == 0 && p == 3)}=
*)
There are two cases for each coin and I need to pick the one with the
smallest number of coins. But the only way I know to begin that is with
a list of rules. I can get a Sequence for the first element of the List
sol but I can't figure how to get the Sequence to a list.
x = (sol[[1]]) // ToRules
(* Sequence[{q -> 1, d -> 2, n -> 1, p -> 2}, {q -> 2, d -> 0, n -> 0,
p -> 2}] *)
I've always had problems figuring out what a Sequence is and the HELP
doesn't really help me. Can someone please suggest how I can use this
sequence to select the {q,d,n,p} set that has the minimum coin count?
It's got me stumped. Thanks.
--
Hi,
To turn this
sq=Sequence[{q -> 1, d -> 2, n -> 1, p -> 2}, {q -> 2, d -> 0, n -> 0,
p -> 2}];
into the list you may plainly write:
lst1=List[sq]
It returns
{{q -> 1, d -> 2, n -> 1, p -> 2}, {q -> 2, d -> 0, n -> 0, p -> 2}}
Now, if I understand you right, you would like to sort out a combination with the minimum sum q+d+n+p, would you?
If yes, one way to do this is as follows:
This removes the rules, but leaves instead the right part of each rule in the list:
lst2 = lst1 /. Rule[x_, y_] -> y
(* {{1, 2, 1, 2}, {2, 0, 0, 2}} *)
This finds the position of the sublist with the minimal sum:
pos = Position[Total[#] & /@ lst2, Min[Total[#] & /@ lst2]][[1, 1]]
(* 2 *)
And this returns the sublist of rules with the minimal sum:
lst1[[pos]]
(* {q -> 2, d -> 0, n -> 0, p -> 2} *)
Have fun, Alexei
Alexei BOULBITCH, Dr., habil.
IEE S.A.
ZAE Weiergewan,
11, rue Edmond Reuter,
L-5326 Contern, LUXEMBOURG
Office phone : +352-2454-2566
Office fax: +352-2454-3566
mobile phone: +49 151 52 40 66 44
e-mail: alexei.boulbitch at iee.lu
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